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Olegator [25]
3 years ago
7

The rate-determining step in the acid-catalyzed dehydration of 2-methylcyclohexanol results in the formation of what type of int

ermediate?

Chemistry
2 answers:
Svetach [21]3 years ago
5 0

Answer:

The rate determining step depends on the

Explanation:

The rate determining step depends on the mechanism of the reaction. If it proceeds by E1 reaction mechanism, it produces 1-methylcyclohexene while the E3 reaction mechanism gives 3-methylcyclohexene. The rate determining step for E1 is an intermediate that is formed when protonation of the hydroxyl group occurs to form H3O+ followed by electrophilic attack on the carbocation formed to absorb the hydrogen making the carbon atom -CH2 and forming a double bond between.

The E3 mechanism is similar only that the attack on the carbon atom is done at the -C3 instead of -C1.

Arisa [49]3 years ago
3 0

Answer:

1-methylcyclohexene which is the major intermediate product

Explanation:

The rate-determining step of a chemical reaction is often the slowest step of a series of steps in that reaction. This step often determines the overall speed of the overall reaction.

In the acid catalysed dehydration of 2-methylcyclohexanol, the intermediate step, which is the rate determining step, produces 1-methylcyclohexene, an unsaturated cycloalkene (which is more stable) with the loss of water.

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2 years ago
What is the theoretical yield of Calcium if we begin with 12.6 grams of Aluminium?
AlladinOne [14]

The question is incomplete, here is the complete question:

The given chemical reaction is:

2Al+3Cu(NO_3)_2\rightarrow 3Cu+2Al(NO_3)_3

What is the theoretical yield of Calcium if we begin with 12.6 grams of Aluminium?

<u>Answer:</u> The theoretical yield of copper is 44.48 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

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Molar mass of aluminium = 27 g/mol

Putting values in equation 1, we get:

\text{Moles of aluminium}=\frac{12.6g}{27g/mol}=0.467mol

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2Al+3Cu(NO_3)_2\rightarrow 3Cu+2Al(NO_3)_3

By Stoichiometry of the reaction:

2 moles of aluminium produces 3 moles of copper

So, 0.467 moles of aluminium will produce = \frac{3}{2}\times 0.467=0.7005mol of copper

Now, calculating the mass of copper  from equation 1, we get:

Molar mass of copper = 63.5 g/mol

Moles of copper = 0.7005 moles

Putting values in equation 1, we get:

0.7005mol=\frac{\text{Mass of copper}}{63.5g/mol}\\\\\text{Mass of copper}=(0.7005mol\times 63.5g/mol)=44.48g

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