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ipn [44]
3 years ago
12

Can some help me do this we have a final tomorrow and i have now idea how to do it. Step by Step explanation and tips If you kno

w any

Chemistry
1 answer:
Romashka-Z-Leto [24]3 years ago
3 0

Answer:

87.27 grams

Explanation:

The mole ratio of nitrogen to hydrogen is 1:3; while that one of hydrogen to the products (ammonia) is 3:2

Thus if 3 moles of hydrogen gas produce 2 moles of ammonia gas

7.7 moles of hydrogen will produce:

(7.7moles×2)/3

77/15 moles

1 mole of ammonia gas has a mass of  14+3=17

since the mass of an atom of nitrogen is 14 while that of hydrogen atom is 1.

Therefore 77/15 moles will have a mass of

77/15 moles × 17=87.27 grams

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What will 3.20 moles of o2 occupy at stp
ludmilkaskok [199]
The molar volume of any ideal gas at STP condition is 22.4 L

3.20 mol x 22.4L / 1 mol = 71.68 L = 71.7 L
4 0
4 years ago
What tools did you use to collect your data? 1.20 Lab: Earth's Surface Processes.
Lyrx [107]

Answer:

I don't know because I don't know about chemistry

6 0
3 years ago
What is the molarity of a nitric acid solution if 43.13 mL 0.1000 M KOH solution is needed to neutralize 30.00 mL of the acid so
Leno4ka [110]

Answer:

0.144M

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

HNO3 + KOH —> KNO3 + H20

From the equation,

nA = 1

nB = 1

From the question given, we obtained the following:

Ma =?

Va = 30.00mL

Mb = 0.1000M

Vb = 43.13 mL

MaVa / MbVb = nA/nB

Ma x 30 / 0.1 x 43.13 = 1

Cross multiply to express in linear form

Ma x 30 = 0.1 x 43.13

Divide both side by 30

Ma = (0.1 x 43.13) /30 = 0.144M

The molarity of the nitric acid is 0.144M

8 0
3 years ago
Express a fraction that is equivalent to a terminating decimals between 0.5 and 0.75.
olya-2409 [2.1K]
0.5 = 1/2 = 2/4 = 4/8 = 8/16 = 16/32…
0.75 = 3/4 = 6/8 = 12/16 = 24/32…

Then you can easily find the fractions in between are: 5/8, 9/16, 11/16, 17/32, 19/32, 21/32, 23/32...
8 0
3 years ago
Boron has two naturally occurring isotopes; B-10 with a mass of 10.01 amu and a natural abundance of 20.00%, and B-11 with a mas
balandron [24]

Atomic mass of boron = 10.81

<h3>What are Isotopes?</h3>

Isotopes are variants of a particular element in which they have the same number of protons but differ in the number of neutrons in the atom.

So, here as we said we have isotopes which weigh 10.01 and 11.01.

Given,

relative abundance of B-10 = 10.1 amu

relative abundance of B- 11 = 11.01 amu

percentage of B-10 = 20%

percentage of B-11 = 80%

Then the relative atomic mass depends upon the relative abundance of various isotopes of that particular element. Suppose an element consists of two isotopes and average atomic mass is equal to

(Relativeabundance(1)×Atomicmass(1)+Relativeabundance(2)×Atomicmass(2)) / (Relativeabundance(1)+Relativeabundance(2))

Atomic mass of boron = (20 × 10.01 + 80 × 11.01) / (80 + 20 )

= 1081/100

= 10.81

To learn more about atomic mass from the given link

brainly.com/question/3187640

#SPJ4

8 0
2 years ago
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