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Nutka1998 [239]
3 years ago
9

A small ferryboat is 3.90 m wide and 6.30 m long. when a loaded truck pulls onto it, the boat sinks an additional 5.00 cm into t

he river. what is the weight of the truck?
Physics
1 answer:
Leya [2.2K]3 years ago
6 0
When the truck's weight is added to the boat, the boat sinks 5 cm deeper,
and displaces additional water whose weight is equal to the weight of the
truck.

The volume of the additional displaced water is

             (3.9 m) x (6.3 m) x (5.0 cm)

         =  (3.9 m) x (6.3 m) x (0.05 m)  =   1.2285 m³ .

The weight of that much water is the weight of the truck.

          Mass of 1 liter of water  =  1 kilogram

          1.2285 m³  =  1,228.5 liters  =  1,228.5 kg of water.

          Weight = (mass) x (gravity)

                      = (1,228.5 kg) x (9.8 m/s²)  =  12,039 Newtons.

                                                                  (about 2,708 pounds) 

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In a large restaurant an average 60% customers ask for water with their meal. A random sample of 10 customers is selected. Find
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Answer:

a)P(6)=0.25

b)p(x

c)p(x\geq3)=0.9878

d)\sigma=\sqrt{2.4}=1.5492

Explanation:

From the question we are told that:

Population percentage p_\%=\60%

Sample size n=10

Let x =customers ask for water

Let y =customers dose not ask for water with their meal  

Generally the equation for y is mathematically given by

y=1-p_\%\\y=1-0.60\\y=0.40

Generally the equation for pmf p(x) is mathematically given by

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a)

Generally the probability that exactly 6 ask for water is mathematically given by

P(x)6=10C_6 (0..6)^6(0.4)^{10-6}

P(6)=0.25

b)

Generally the probability that  less than 9 ask for water with meal  is mathematically given by

p(xg)

p(x

p(x

p(x

c)

Generally the probability that  at least 3 ask for water with meal  is mathematically given by

p(x\geq3)=1-p(x

p(x\geq3)=1-[p(0)+p(1)+p(2)]

p(x\geq3)=1-[0.00001+0.0015+0.0106]

p(x\geq3)=1-[0.0122]

p(x\geq3)=0.9878

d)

Generally the mean and standard deviation of sample size is mathematically given by

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Standard deviation

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\sigma=\sqrt{2.4}=1.5492

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A 980 kg roller coaster cart is traveling along a track at 17 m/s before it rolls down a 30 m tall hill (Point A). What will be
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The kinetic energy halfway the hill is 2.86\cdot 10^5 J

Explanation:

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U_A +K_A = U_B + K_B

where

U_A=mgh_A is the initial potential energy, at point A, with

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h_A = 30 m (height at point A)

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Here we are interested in finding K_B, so by re-arranging the equation and substituting we find:

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Answer:

Pls see attached file

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