Which example best represents translational kenetic energy

Which type of fitness is not based on performance?

Aneli [31]

Fitness can be measured during the actual performance.
Which means that there are a lot of factors that can affect agility, speed, and coordination beside the physical factors itself. Meanwhile, flexibility solely depends on the physical Factors.

The answer is flexibility .

Hope this helps (:

4 0

3 years ago

An astronaut on a small planet wishes to measure the local value of g by timing pulses traveling down a wire which has a large o

kondor19780726 [428]

Answer:

2.56 m/s²

Explanation:

A standing wave is produced in the wire, its frequency f = n/2l√(T/μ). For the fundamental frequency, n = 1.

f = 1/2l√(T/μ)

where l = length of wire = 1.60 m, T₁ = tension in wire = weight of object = m₁g (neglecting wires mass), m₁ = mass of object = 3.00 kg, g = acceleration due to gravity on the small planet, μ = linear density of wire = m₀/l , m₀= mass of wire = 4.30 g = 0.0043 kg and f = 1/T where T = period of pulse = 59.9 ms = 0.0599 s

f = 1/2l√(T₀/μ) = 1/T ⇒ T₁ = 4l²μ/T²

m₁g = 4l²μ/T²

g = 4l²μ/m₁T² = 4l²m₀/l/m₁T² = 4lm₀/m₁T²

g = 4lm₀/m₁T² = 4 × 1.60 × 0.0043/(3.00 × 0.0599²) = 2.56 m/s²

4 0

3 years ago

Calculate the first and second velocities of the car with four washers attached to the pulley, using the formulas v1 = 0.25 m /

Blizzard [7]

Answer:

0.28 that is for the 25 and for 50 is 0.56

Explanation:

7 0

3 years ago

Read 2 more answers

A proton and an electron are released from rest, with only the electrostatic force acting. Which of the following statements mus

Anit [1.1K]

Answer:

Their kinetic energy will increase but potential energy will decrease.

Explanation:

Given that

Initial velocities of electron and proton is zero.

We know that ,electron have negative charge and proton have positive charge it means that they will attract to each other.We know that opposite charge attract to each other and same charge repels to each other.

It means that the velocities of proton and electron will increase and that leads to increase in the kinetic energy of proton and electron.

We know that potential energy U

$U\alpha -\dfrac{1}{r}$

So when r will decrease then U will increase but in negative direction it means that U will decrease.

So we can say that their kinetic energy will increase but potential energy will decrease.

5 0

3 years ago

An 85,000 kg stunt plane performs a loop-the-loop, flying in a 260-m-diameter vertical circle. at the point where the plane is f

konstantin123 [22]

A) When the plane is flying straight down, there are three forces acting on it:
- the centripetal force $F=m \frac{v^2}{r}$ , directed toward the center of the circle (so, horizontally)
- the weight of the plane: $W=mg$ , downward, so vertically
- a third force, given by the propulsion of the plane, which is accelerating it towards the ground (because the problem says that the plane has an acceleration of a=12 m/s^2 towards the ground)

The radius of the circle is $r= \frac{260 m}{2} = 130 m$ , so the centripetal force acting on the plane is
$F_c=m \frac{v^2}{r} = \frac{(85000 kg)(55 m/s)^2}{130 m}=1.98 \cdot 10^6 N$
On the vertical axis, we have two forces: the weight
$W=mg=(85000 kg)(9.81 m/s^2)=8.34 \cdot 10^5 N$
and the other force F given by the propulsion. Since we know that their sum should generate an acceleration equal to $a=12 m/s^2$ , we can find the magnitude of this other force F by using Newton's second law:
$F+mg=ma$
$F=m(a-g)=(85000kg)(12 m/s^2-9.81 m/s^2)=1.86 \cdot 10^5 N$

So, the net force acting on the plane will be the resultant of the centripetal force (acting in the horizontal direction) and the two forces W and F (acting in the vertical direction):
$R= \sqrt{(F_c^2+(W+F)^2}=$
$= \sqrt{(1.98\cdot 10^6N)^2+(8.34 \cdot 10^5N+1.86 \cdot 10^5 N)^2} =2.23 \cdot 10^6 N$

(b) The tangent of the angle with respect to the horizontal is the ratio between the sum of the forces in the vertical direction (taken with negative sign, since they are directed downward) and the forces acting in the horizontal direction, so:
$\tan \theta = \frac{-(W+F)}{F_c}= -0.5$
And so, the angle is
$\theta = \arctan (-0.5)=-26.8 ^{\circ}$

7 0

3 years ago