Please select the word from the list that best fits the definition

I don't understand how to find the frequency and period of wavelengths. Can anyone help me?

nordsb [41]

Frequency of a wave =

   (speed of the wave) divided by (wavelength)
or
   (1) divided by (period of the wave) .

Period of the wave =

   (wavelength) divided by (speed of the wave)
or
   (1) divided by (frequency of the wave) .

3 0

3 years ago

An electron is trapped in an infinite square-well potential of width 0.6 nm. If the electron is initially in the n = 4 state, wh

grandymaker [24]

Answer:

E₁ = 1.042 eV

E₄₋₃= 7.29 eV

E₄₋₂= 12.50 eV

E₄₋₁= 15.63 eV

E₃₋₂= 5.21eV

E₃₋₁= 8.34eV

E₂₋₁= 3.13eV

Explanation:

The energy in an infinite square-well potential is giving by:

$E = \frac {h^{2} n^{2}}{8mL^{2}}$

where, h: Planck constant = 6.62x10⁻³⁴J.s, n: is the energy state, m: mass of the electron and L: widht of the square-well potential

The energy of the electron in the ground state, n = 1, is:

$E_{1} = \frac {(6.62 \cdot 10^{-34})^{2} (1)^{2}}{(8) (9.11 \cdot 10^{-31}) (0.6 \cdot 10^{-9} m)^{2}}$

$E_{1} = 1.67 \cdot 10^{-19} J = 1.042 eV$

The photon energies that are emitted as the electron jumps to the ground state is the difference between the states:

$E_{\Delta n} = \Delta n^{2} E_{1}$

$E_{(4 - 3)} = (4^{2} - 3^{2}) 1.042 eV = 7.29eV$

$E_{(4 - 2)} = (4^{2} - 2^{2}) 1.042 eV = 12.50eV$

$E_{(4 - 1)} = (4^{2} - 1^{2}) 1.042 eV = 15.63eV$

$E_{(3 - 2)} = (3^{2} - 2^{2}) 1.042 eV = 5.21eV$

$E_{(3 - 1)} = (3^{2} - 1^{2}) 1.042 eV = 8.34eV$

$E_{(2 - 1)} = (2^{2} - 1^{2}) 1.042 eV = 3.13eV$

Have a nice day!

7 0

3 years ago

When doing scientific research ,the sources used should be ?

quester [9]

Answer: Reliable and trusted

6 0

3 years ago

Read 2 more answers

In the standing broad jump, one squats and then pushes off with the legs to see how far one can jump. Suppose the extension of t

muminat

<h2>⇒Answer:</h2>

In the standing broad jump, one squats and then pushes off with the legs to see how far one can jump. Suppose the extension of the legs from the crouch position is 0.600 m and the acceleration achieved from this position is 1.25 times the acceleration due to gravity, g . How far can they jump? State your assumptions. (Increased range can be achieved by swinging the arms in the direction of the jump.)

Step-by-Step Solution:

Solution 35PE

This question discusses about the increased range. So, we shall assume that the angle of jumping will be as the horizontal range is maximum at this angle.

Step 1 of 3<

/p>

The legs have an extension of 0.600 m in the crouch position.

So, m

The person is at rest initially, so the initial velocity will be zero.

The acceleration is m/s2

Acceleration m/s2

Let the final velocity be .

Step 2 of 3<

/p>

Substitute the above given values in the kinematic equation ,

m/s

Therefore, the final velocity or jumping speed is m/s

Explanation:

3 0

3 years ago

Read 2 more answers

Which of the following is NOT a result of supernova explosions? The neutron core is completely destroyed. Any planets within a f

DanielleElmas [232]

Answer:

The neutron core is completely destroyed

Explanation:

A earth - supernova is an explosion resulting to the death of a star that occurs close enough to the earth but this does not completely destroy a star. Supernovae are the most violent explosions in the universe. But they do not explode like a bomb explodes, blowing away every bit of the original bomb. Rather, when a star explodes into a supernova, its core survives. The reason for this is that the explosion is caused by a gravitational rebound effect and not by a chemical reaction. Stars are so large that the gravitational forces holding them together are strong enough to keep the nuclear reactions from blowing them apart. It is the gravitational rebound that blows apart a star in a supernova.

4 0

3 years ago