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malfutka [58]
3 years ago
9

A rope is vibrating at high frequency. The length of the rope is 2.40 meters. A snapshot of the rope at a given moment in time

Physics
1 answer:
Vinvika [58]3 years ago
3 0

Answer:

λ = L / # _ periods

Explanation:

We don't have the image of the string, but a wavelength is the minimum distance when the wave repeats, therefore the distance between two consecutive maxima is the wavelength in the string

A method used to decrease the error is to measure the distance in several consecutive maxima and divide the number of them, in this way the error in the measurements is divided between all the points, so the value of the wavelength is more exact

               λ = L / # _ periods

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A rectangular plate has a length of (21.7 ± 0.2) cm and a width of (8.2 ± 0.1) cm. Calculate the area of the plate, including it
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Answer:

(177.94 ± 3.81) cm^2

Explanation:

l + Δl = 21.7 ± 0.2 cm

b + Δb = 8.2 ± 0.1 cm

Area, A = l x b = 21.7 x 8.2 = 177.94 cm^2

Now use error propagation

\frac{\Delta A}{A}=\frac{\Delta l}{l}+\frac{\Delta b}{b}

\frac{\Delta A}{A}=\frac{0.2}{21.7}+\frac{0.1}{8.2}

\Delta A=177.94 \times \left ( 0.0092 + 0.0122 \right )=3.81

So, the area with the error limits is written as

A + ΔA = (177.94 ± 3.81) cm^2

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