Answer:
speed in km/min:
0.3km/min
speed in km/h:
18km/h
speed in m/s:
5m/s
Explanation:
the average speed is defined as:
where 
is the speed, 
is the distance traveled, and 
is the time
according to the statement:
and
(10 minutes are equal to a sixth of an hour which is 600 seconds)
Because the units in which the speed is required are not indicated, here are some options for the answer:
Depending on the units in which you need the speed, are the quantities you should use.
Speed in km / h (kilometers per hour):
speed in m / s (meters per second):
or the speed in km/min (kilometers per minute)
1.6 m/s west is the answer
I don’t see a picture but unbalanced forces could be two boys pushing with a combined force of 400 Newton’s but the surface of what the box is laying on being 600 meaning since the ground is creating a higher force in the form of friction it will slow the boys down. When forces are unbalanced it means that the object can not be still or moving at a constant speed when one force is greater by a significant amount the object either slows quickly or accelerates fast depending on which factor is greater.
Answer:
The false statement is 'Electric field lines form closed loops'.
Explanation:
- Electric field lines originate from positive end and terminates at negative end,i.e., field lines are inward in direction to the negative charges and outward from the positive charges.
- These lines when close together represents high intensity and when far apart shows low intensity of the field.
- These lines do not intersect, as the tangent drawn on these lines provides us with the field direction and intersection of these lines means two field directions which is not possible.
- These lines unlike magnetic field lines do not form closed loops as they do not turn around but originate at positive end and terminates at negative end which ensures no loop formation.
Answer:
Explanation:
As we know that the ball is projected upwards so that it will reach to maximum height of 16 m
so we have
here we know that
also we have
so we have
Now we need to find the height where its speed becomes half of initial value
so we have
now we have
