Answer:
To identify the momentum of object 1, you must multiply mass (m) and velocity(v) to find momentum.
Object 1 has momentum of 8 kg. m/s before collision.
Object 1 has momentum of 0 kg. m/s before collision.
The combined mass after the collision had a total momentum of 8 kg. m/s.
Explanation:
Momentum of the object is given by,
Momentum = mass × velocity
For object 1:
Momentum = mass × velocity
Momentum = 2 × 4
Momentum = 8 kg. m/s
For object 2:
Momentum = mass × velocity
Momentum = 6 × 0
Momentum = 0 kg. m/s
For object 1 + object 2:
Momentum = mass × velocity
Momentum = 8 × 1
Momentum = 8 kg. m/s
To identify the momentum of object 1, you must multiply mass (m) and velocity(v) to find momentum.
Object 1 has momentum of 8 kg. m/s before collision.
Object 1 has momentum of 0 kg. m/s before collision.
The combined mass after the collision had a total momentum of 8 kg. m/s.
Answer:
Another danger that comes with intrapreneurs is the lack of patience from other people in the office. To people who have worked their whole lives in one company, they might expect to see instant results from somebody who has waltzed in and promised big things.
An object is in motion if its distance relative to another object is changing. To tell if an object is moving, you use a reference point. If an object's distance from another object [reference point] is changing. A place or object used for comparison to determine if something is in motion.
Answer:
a) p = m1 v1 + m2 v2
, b) dp / dt = m1 a1 + m2 a2
, c) It is equivalent to force
dp / dt = 0
Explanation:
In this problem we have two blocks and the system is formed by the two bodies.
Part A. Initially they ask us to find the moment of the whole system
p = m1 v1 + m2 v2
Part B.
Find the derivative
dp / dt = m1 dv1dt + m2 dv2 / dt
dp / dt = m1 a1 + m2 a2
Part C.
Let's analyze the dimensions
m a = [kg] [m / s2] = [N]
It is equivalent to force
Part d
Acceleration is due to a net force applied
Part e
The acceleration of block 1 is due to the force exerted by block 2 during the moment change
Part f
Force of block 1 on block 2
True f12 = m1a1 f21 = m2a2
Part g
By the law of action and reaction are equal magnitude F12 = f21
Part H
dp / dt = 0
Isolated system F12 = F21 and the masses are constant. The total moment is only redistributed
