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Nonamiya [84]
3 years ago
15

7. A scientific theory can change if (2 points) nobody wants to believe it it becomes too old the scientist who discovered it di

es we discover some new facts
Physics
1 answer:
allochka39001 [22]3 years ago
4 0

Answer: this is true

Explanation: another one is if it is disproved

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The second-order decomposition of hi has a rate constant of 1.80 x 10−3 m−1 s−1. How much hi remains after 45.6 s if the initial
zlopas [31]

Answer:

2.9 M

Explanation:

The concentration-time equation for a second order reaction is:

1/[A] = kt + 1/[A°]

Where,

A = concentration remaining at time, t

A° = initial concentration

k = rate constant

1/[A] = (1.80 x 10^-3) * (45.6) + 1/3.81

1/[A] = 0.345

= 1/0.345

= 2.9 M.

6 0
3 years ago
How did Archimedes measure the mass of the block of gold?
MA_775_DIABLO [31]
Archimedes found a piece of gold and a piece of silver with exactly the same mass. He dropped the gold  into a bowl filled to the brim with water and measured the volume of water that spilled out. Then he did the same thing with the piece of solver. Although both metals had the same mass, the silver gad a larger volume; therefore, it displaced more water than the gold did. That's because the silver was less dense than gold. Afterwards he applied the same method to the crown for the king he served who had got a new crown from a jeweler who gave it to him. Archimedes found a piece of pure gold that had the same mass as the crown. He placed the pure gold chuck and the crown in water, one at a time. The crown displaced more water the piece of gold. Therefore, its density was less than pure gold.  
5 0
2 years ago
An 800-kHz radio signal is detected at a point 8.5 km distant from a transmitter tower. The electric field amplitude of the sign
Temka [501]

Answer:

Explanation:

Given that,

Frequency of radio signal is

f = 800kHz = 800,000 Hz.

Distance from transmitter

d = 8.5km = 8500m

Electric field amplitude

E = 0.9 V/m

The average energy density can be calculated using

U_E = ½•ϵo•E²

Where ϵo = 8.85 × 10^-12 F/m

Then,

U_E = ½ × 8.85 × 10^-12 × 0.9²

U_E = 3.58 × 10^-12 J/m²

The average electromagnetic energy density is 3.58 × 10^-12 J/m²

6 0
3 years ago
Read 2 more answers
A negative test charge will accelerate toward regions of ________ electric potential and ________ electric potential energy.
dalvyx [7]

Answer: higher and lower

Explanation:

 charge in an electric field will experience a force in the direction of decreasing potential energy. Since the electric potential energy of a negative charge is equal to the charge times the electric potential the direction of decreasing electric potential energy is the direction of increasing electric potential.

5 0
3 years ago
Which of the following values represents an index of refraction of an actual material?
Airida [17]

The answer is <em>B. 5/4</em> or <em>1.25</em>

3 0
3 years ago
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