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fredd [130]
3 years ago
10

A 500 kg car is moving at 30 m/s. The driver sees a barrier ahead. If the car takes 100 m to come to rest, what is the magnitude

of the force necessary to stop the car?
How do you solve this question?
Physics
1 answer:
FromTheMoon [43]3 years ago
7 0

Answer:

F = 2250 [N]

Explanation:

In order to solve this problem, we must first use the following equation of kinematics.

v_{f}^{2} =v_{o}^{2}-2*a*x

where:

Vf = final velocity = 0 (come to rest)

Vo =  initial velocity = 30 [m/s]

a = acceleration or desaceleration [m/s²]

x = distance = 100 [m]

(0)=30^{2} -2*a*100\\900 =  200*a\\a = 4.5 [m/s^{2}]

Now we must use the following equation of kinetics, which is based on Newton's second law that explains that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = force [N]

m = mass = 500 [kg]

a = acceleration = 4.5 [m/s²]

F = 500*4.5\\F = 2250 [N]

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prisoha [69]

Answer:

Explanation:

As the full spectrum of visible light travels through a prism, the wavelengths separate into the colors of the rainbow because each color is a different wavelength. Violet has the shortest wavelength, at around 380 nanometers, and red has the longest wavelength, at around 700 nanometers.

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2 years ago
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The volume of a gas is increased six times the original volume by heating it. If the original temperature of
OleMash [197]

The final temperature of the gas given the data from the question is 1527 °C

<h3>Data obtained from the question</h3>
  • Initial volume (V₁) = V
  • Initial temperature (T₁) = 27 °C = 27 + 273 = 300 K
  • Final volume (V₂) = 6V
  • Final temperature (T₂) =?

<h3>How to determine the new temperature </h3>

The final temperature of the gas can be obtained by using the Charles' law equation as illustrated below:

V₁ / T₁ = V₂ / T₂

V / 300 = 6V / T₂

Cross multiply

V × T₂ = 300 × 6V

Divide both side by V

T₂ = (300 × 6V) / V

T₂ = 1800 K

Subtract 273 from 1800 K to express in degree celsius

T₂ = 1800 – 273

T₂ = 1527 °C

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6 0
2 years ago
Calculate the tension (in N) in a vertical strand of spiderweb if a spider of mass 5.00 ✕ 10-5 kg hangs motionless on it.
Mandarinka [93]

Answer:

4.9 x 10⁻⁴N

Explanation:

Given parameters:

Mass of the vertical strand of spiderweb  = 5 x 10⁻⁵kg

Unknown:

Tension in the vertical strand  = ?

Solution:

The tension is the vertical strand will be the weight of the strand.

  Weight of strand  = mg

m is the mass

g is the acceleration due to gravity = 9.8m/s²

Tension in the vertical strand  = 5 x 10⁻⁵kg  x 9.8m/s²

Tension in the vertical strand  = 4.9 x 10⁻⁴N

3 0
3 years ago
A satellite that goes around the earth once every 24 hours iscalled a geosynchronous satellite. If a geosynchronoussatellite is
lesantik [10]

Answer:

35870474.30504 m

Explanation:

r = Distance from the surface

T = Time period = 24 h

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

m = Mass of the Earth =  5.98 × 10²⁴ kg

Radius of Earth = 6.38\times 10^6\ m

The gravitational force will balance the centripetal force

\dfrac{GMm}{R^2}=m\dfrac{v^2}{R}\\\Rightarrow v=\sqrt{\dfrac{GM}{R}}

T=\dfrac{2\pi r}{v}\\\Rightarrow T=\dfrac{2\pi r}{\sqrt{\dfrac{GM}{r}}}

From Kepler's law we have relation

T^2=\dfrac{4\pi^2r^3}{GM}\\\Rightarrow r^3=\dfrac{T^2GM}{4\pi^2}\\\Rightarrow r=\left(\dfrac{(24\times 3600)^2\times 6.67\times 10^{-11}\times 5.98\times 10^{24}}{4\pi^2}\right)^{\dfrac{1}{3}}\\\Rightarrow r=42250474.30504\ m

Distance from the center of the Earth would be

42250474.30504-6.38\times 10^6=\mathbf{35870474.30504\ m}

8 0
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Answer:

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7 0
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