Answer:
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For t1:
t1 = square root of 2h1 / g = square root of 2 * 0.5 / 9.8 = 0.319 sec
For t2:
t2 = sqaure root of 2h2 / g = square root of 2 * 1.0 / 9.8 = 0.451 sec
Wherein:
t = time(s) for the vertical movement
h= height
g = gravity (using the standard 9.8 m/sec measurement)
d1 = 1*0.319 = 0.319 m
d2 = 0.5 * 0.451 = 0.225 m
Where:
d = hor. distance
ratio = d1:d2
= 0.319 : 0.225
=3.19 : 2.25
The answer is 3.19 : 2.25
If all the mass of fuel and oxygen is burned to form gases of combustion, the downward velocity of these gases would be 12,505 m/s.
<h3>
Conservation of linear momentum</h3>
The principle of conservation of linear momentum states that, the total momentum of an isolated system is constant.
The downward velocity of thes gases is calculated as follows;
v1(m1 + m2) = v2(m2)
305(1000 + 25) = v2(25)
312,625 = 25v2
v2 = 312,625/25
v2 = 12,505 m/s
Thus, If all the mass of fuel and oxygen is burned to form gases of combustion, the downward velocity of these gases would be 12,505 m/s.
Learn more about linear momentum here: brainly.com/question/7538238
Answer:
67.9 kg*m/s
Explanation:
Pi = 38 kgm/s
F = 88.3N and ∆t = 0.338s
Final momentum Pf = Pi + F∆t = 38 + (88.3)(0.338) = 38 + 29.8454
=) Pf = 67.8454 kgm/s = 67.85kg*m/s
Your answer is 67.9kg*m/s with three significant figures
hope this helps your troubles!
The answer is C. elastic potential energy
