A tank of water is separated into two sections. Hot green water is placed on one side of the tank and clear cold water is placed
2 answers:
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Answer:
0.29D
Explanation:
Given that
F = G M m / r2
F = GM(6m) / (D-r)2
G Mm/r2 = GM(6m) / (D-r)2
1/r2 = 6 / (D-r)2
r = D / (Ö6 + 1)
r = 0.29 D
See diagram in attached file
In a velocity-time graph, the area under the curve represents the distance.
The distance traveled from 10s to 18 s is
Final Answer: The distance traveled is 40 m from time 10 s to 18 s.
(a) The lowest frequency (called fundamental frequency) of a wire stretched under a tension T is given by
where
L is the wire length
T is the tension
m is the wire mass
In our problem, L=10.9 m, m=55.8 g=0.0558 kg and T=253 N, therefore the fundamental frequency of the wire is
b) The frequency of the nth-harmonic for a standing wave in a wire is given by
where n is the order of the harmonic and f1 is the fundamental frequency. If we use n=2, we find the second lowest frequency of the wire:
c) Similarly, the third lowest frequency (third harmonic) is given by
where
L is the wire length
T is the tension
m is the wire mass
In our problem, L=10.9 m, m=55.8 g=0.0558 kg and T=253 N, therefore the fundamental frequency of the wire is
b) The frequency of the nth-harmonic for a standing wave in a wire is given by
where n is the order of the harmonic and f1 is the fundamental frequency. If we use n=2, we find the second lowest frequency of the wire:
c) Similarly, the third lowest frequency (third harmonic) is given by