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user100 [1]
2 years ago
12

Please no links. Answer properly please and thank you. Perform the following mathematical operation and report the answer to the

correct number of significant figures. 0.092/8.3

Chemistry
2 answers:
kirill [66]2 years ago
4 0

Answer:

The answer is 0.011

MA_775_DIABLO [31]2 years ago
3 0
i'm extremely sorry if this is wrong but i got 0.0110843 or as a fraction 23/2075 i'll write my work in the comments
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My guess on that molecule is nucleus , sorry if it’s not correct
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3 years ago
I don't know please help me which one I sent you a picture​
umka2103 [35]

Answer:

intermolecular forces

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3 years ago
Name the following ionic compounds, keeping in mind that a transition metal cation must include its charge. ____________________
Lilit [14]

Answer :

(a) The name for TiO_2 is titanium(IV) oxide.

(b) The name for BaCl_2 is barium chloride.

(c) The name for CuCl_3 is copper(III) chloride.

(d) The name for KI is potassium iodide.

(e) The name for SrCl_2 is strontium chloride.

(f) The name for CuBr_2 is copper(II) bromide.

Explanation :

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

Ionic compound are usually formed when a metal reacts with a non-metal.

The nomenclature of ionic compounds is given by:

1. Positive ion is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

3. In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.

(a) TiO_2

TiO_2 is an ionic compound because titanium element is a metal and oxygen element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on tin is (+4) and the the charge on oxygen is (-2). Thus, the name for TiO_2 is titanium(IV) oxide.

(b) BaCl_2

BaCl_2 is an ionic compound because barium element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on barium is (+2) and the the charge on chlorine is (-1). Thus, the name for BaCl_2 is barium chloride.

(c) CuCl_3

CuCl_3 is an ionic compound because copper element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on copper is (+3) and the the charge on chlorine is (-1). Thus, the name for CuCl_3 is copper(III) chloride.

(d) KI

KI is an ionic compound because potassium element is a metal and iodine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on potassium is (+1) and the the charge on iodine is (-1). Thus, the name for KI is potassium iodide.

(e) SrCl_2

SrCl_2 is an ionic compound because strontium element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on strontium is (+2) and the the charge on chlorine is (-1). Thus, the name for SrCl_2 is strontium chloride.

(f) CuBr_2

CuBr_2 is an ionic compound because copper element is a metal and bromine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on copper is (+2) and the the charge on bromine is (-1). Thus, the name for CuBr_2 is copper(II) bromide.

3 0
3 years ago
T = 409.5 K, P = 1.50 atm: V = ?L
Molodets [167]

Explanation:

T = 409.5 K, P = 1.50 atm: V = 22.4 L The ideal gas law is: PV = nRT where. P = pressure. V = volume n = number of moles.

7 0
2 years ago
Describe what happened when sodium chloride (salt) was placed in water in the video What happens when stuff dissolves?"
Sonja [21]

Answer:

-

Explanation:

Water molecules pull the sodium and chloride ions apart, breaking the ionic bond that held them together. After the salt compounds are pulled apart, the sodium and chloride atoms are surrounded by water molecules, as this diagram shows. Once this happens, the salt is dissolved, resulting in a homogeneous solution.

6 0
2 years ago
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