Answer:
-100.125
Explanation:
We are given
CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (l) △H = -890.0 kJ/mol
The given information is for complete reaction
we have 1.8grams of Methane
Molar mass of CH4 = 16
No of moles of Methane = 1.8/ 16
= 0.1125
So the amount of the heat will be released from the amount of the methane
Q = No of moles*( -890.0 kJ/mol)
= 0.1125*(-890)
= -100.125kJ/mole
Therefore the amount of Energy released from 1.8 grams of methane is equal to -100.125
The heterogeneous mixture that has very small dispersed particles and stays mixed for a long time is colloid. Because colloid has particles that are small enough to suspended but are as large that they can scatter light.
Answer:
40.32L
Explanation:
So we know that 22.4 Liters is one mole of a gass so we can set up an equation to test that
1mole 1.8mole
_____ = _____
22.4L x
and then cross multiply so you get 40.32L
Electronic Configuration of Cu⁴⁺ is written using these two steps;
Step I:
Write the Electronic Configuration of Copper (Cu).
As Atomic Number of Cu = 29
So,
1s², 2s², 2p⁶, 3s², 3p⁶, 3d¹⁰, 4s¹
Rearranging it in order of increasing orbital energy,
1s², 2s², 2p⁶, 3s², 3p⁶, 4s¹, 3d¹⁰
Or,
Cu = [Ar] 4s¹, 3d¹⁰
Step II:
Now, the Cu⁴⁺ ion has lost 4 electrons, So one electron from 4s and 3 electrons from 3d orbital are removed, The resulting electronic configuration becomes,
Cu⁴⁺ = [Ar] 3d⁷
<u>Answer:</u> The mass of water produced in the reaction is 97.2 grams
<u>Explanation:</u>
We are given:
Moles of calcium hydroxide = 2.70 moles
The chemical equation for the reaction of calcium hydroxide and HCl follows:
By Stoichiometry of the reaction:
1 mole of calcium hydroxide produces 2 moles of water
So, 2.70 moles of calcium hydroxide will produce = 
of HCl
To calculate mass for given number of moles, we use the equation:
Molar mass of water = 18 g/mol
Moles of water = 5.40 moles
Putting values in above equation, we get:
Hence, the mass of water produced in the reaction is 97.2 grams
