#7 is D because you move the decimal 4 places
Producers produce a product
Consumers buy that product
It is a homogenous solution because the powder is suspended in the liquid and there is no difference between any parts of it.
The law of conservation has been stated that the mass and energy has neither be created nor destroyed in a chemical reaction.
The law of conservation has been evident when there has been an equal number of atoms of each element in the chemical reaction.
<h3>Conservation law</h3><h3 />
The given equation has been assessed as follows:
The reactant has absence of hydrogen, while hydrogen has been present in the product. Thus, the reaction will not follow the law of conservation.
The number of atoms of each reactant has been different on the product and the reactant side. Thus, the reaction will not follow the law of conservation.
The reactant has the presence of carbon, while it has been absent in the reactant. Thus, the reaction will not follow the law of conservation.
The product has the presence of hydrogen, while it has been absent in the reactant. Thus, the reaction will not follow the law of conservation.
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PH of a solution will be <span>higher than 7
</span>
Ammonium cyanide is a salt formed by hydrogen cyanide and ammonia. Ammonia is a weak base and hydrogen cyanide is a weak acid.
NH₄CN + H₂O ⇒ NH₃ + HCN
NH₄⁺ + H₂O -----> H₃O⁺ + NH₃
CN⁻ + H₂O -----> HCN + OH⁻
Although both compounds are weak electrolytes, NH₃ is somewhat stronger base than HCN is a strong acid, so the solution reacts alkaline. We can prove this using Ka and Kb values:
Ka(HCN) = 4.9 x × 10⁻¹⁰
Kb(NH₃) = 1.8 × 10⁻⁵<span>
Kw= </span>1.0 × 10⁻¹⁴
Let's first calculate Ka for NH₄⁺:
Ka(NH₄⁺) x Kb(NH₃<span>) = pKw
</span>Ka(NH₄⁺) = Kw/Kb(NH₃) = 5.6 x 10⁻¹⁰
Then, Kb for CN⁻:
Kb(CN⁻) x Ka(HCN) = pKw
Kb(CN⁻) = Kw/Ka(HCN) = 2 x 10⁻⁵
From this, we can see that the acid constant NH4⁺ is much lower than the base constant of CN⁻, which will say that the solution of NH₄CN will react slightly alkaline because of the higher presence of hydroxyl ions in solution.