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bekas [8.4K]
3 years ago
13

How does fission and fusion affect an atoms nucleus differently?

Physics
1 answer:
Nata [24]3 years ago
5 0

When a heavy nucleus breaks up into two or more fragments with the liberation of energy, the process is called fission.

When two light nuclei fuse together to form a comparatively heavy nucleus, the process is called fusion. Both processes are accompanied by release of energy.

The most common example of fission is the fission of Uranium nucleus, which absorbs a slow neutron and breaks into Barium, Krypton, a few neutrons and energy.

U(235)+neutron→Ba(139)+Kr(94)+3 neutrons+200 MeV

Each fission releases around 200 MeV of energy.

The fusion reaction is responsible for energy generated by stars.

Protons in the stars combine to form a Helium nucleus with the liberation of energy.

4 protons→Helium+2 positrons+ nuetirnos+ 26.7 MeV

Fusion reactions can happen only at very high temperatures, which is required ,so that the protons have enough kinetic energy to overcome their mutual electrostatic repulsion. The temperatures that can result in fusion are of the order 10^8 K is present in stars , hence stars generate energy by fusion.

However, such temperatures are difficult to maintain and control on Earth, and hence controlled fusion reaction is still not available commercially. Experiments are on , using large magnetic fields to contain the ions that undergo fusion, since no container can hold the nuclei while they undergo fusion.

Fusion is also called clean energy, since the byproducts of fusion are not radioactive, but many fission byproducts are generally radioactive.

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4 0
3 years ago
A force is applied to an ideal spring (initially in its equilibrium position) and does 1.9 JJ of work stretching it 2.2 cmcm . H
Verdich [7]

Answer:

W=16.58J

Explanation:

initial information we have

work: W=1.9J

stretched distance: x=2.2cm=0.022m

from this, we can find the value of the constant of the spring k, with the equation for work in a spring:

W=\frac{1}{2} kx^2

substituting known values:

1.9J=\frac{1}{2}k(0.022)^2\\

and clearing for k:

k=\frac{2(1.9J)}{0.022^2} \\k=7,851.24

and now we want to know how much work is done when we stretch the spring a distance of 6.5cm from equilibrium, so now x is:

x=6.5cm=0.065m

and using the same formula for work, with the value of k that we just found:

W=\frac{1}{2} kx^2

W=\frac{1}{2}(7851.24)(0.065)^2\\W=16.58J

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3 years ago
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That waves travel faster than the wave lenght!
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Determine the mass of Ar in 1.00 liter of a gas mixture at 25oC which contains 0.300 atm of Ne and has a total pressure of 4.00
sergejj [24]

Answer:

The mass of Ar is 36.91g

Explanation:

The gas mixture consist of Neon(Ne) and Argon(Ar)

Partial pressure of Ar = total pressure of mixture - partial pressure = 4 - 0.3 = 3.7 atm

Mole fraction of Ar = partial pressure of Ar ÷ total pressure of mixture = 3.7/4 = 0.925

Mass of Ar = 0.925 × molecular weight of Ar = 0.925 × 39.9 = 36.91g

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