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bekas [8.4K]
3 years ago
13

How does fission and fusion affect an atoms nucleus differently?

Physics
1 answer:
Nata [24]3 years ago
5 0

When a heavy nucleus breaks up into two or more fragments with the liberation of energy, the process is called fission.

When two light nuclei fuse together to form a comparatively heavy nucleus, the process is called fusion. Both processes are accompanied by release of energy.

The most common example of fission is the fission of Uranium nucleus, which absorbs a slow neutron and breaks into Barium, Krypton, a few neutrons and energy.

U(235)+neutron→Ba(139)+Kr(94)+3 neutrons+200 MeV

Each fission releases around 200 MeV of energy.

The fusion reaction is responsible for energy generated by stars.

Protons in the stars combine to form a Helium nucleus with the liberation of energy.

4 protons→Helium+2 positrons+ nuetirnos+ 26.7 MeV

Fusion reactions can happen only at very high temperatures, which is required ,so that the protons have enough kinetic energy to overcome their mutual electrostatic repulsion. The temperatures that can result in fusion are of the order 10^8 K is present in stars , hence stars generate energy by fusion.

However, such temperatures are difficult to maintain and control on Earth, and hence controlled fusion reaction is still not available commercially. Experiments are on , using large magnetic fields to contain the ions that undergo fusion, since no container can hold the nuclei while they undergo fusion.

Fusion is also called clean energy, since the byproducts of fusion are not radioactive, but many fission byproducts are generally radioactive.

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An opera singer who is a baritone, lowers his pitch and raises his voice for a song. Which best describes how the resulting soun
Usimov [2.4K]

Answer: 3.

Explanation:

The correct answer is a higher amplitude and lower frequency. Since an opera singer is lowering his pitch it means that he is creating higher amplitude and because he is raising his voice for a song with that higher amplitude he is creating lower frequency.

8 0
2 years ago
A car starts from 0 m along a road and accelerates at 0.5 m/s^2 to the right. A second car starts from 1000 m along the road and
Brrunno [24]

Answer:

e) 31.6 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Equation of motion

s=ut+\frac{1}{2}at^2\\\Rightarrow s_1=0\times t+\frac{1}{2}\times 0.5\times t^2\\\Rightarrow s_1=\frac{1}{2}0.5t^2\ m

s=ut+\frac{1}{2}at^2\\\Rightarrow s_2=0\times t+\frac{1}{2}\times 0.5\times t^2\\\Rightarrow s_2=\frac{1}{2}1.5t^2\ m

s_1+s_2=1000

\\\Rightarrow 1000=\frac{1}{2}0.5t^2+\frac{1}{2}1.5t^2\\\Rightarrow 1000=\frac{0.5t^2+1.5t^2}{2}\\\Rightarrow 1000=\frac{2t^2}{2}\\\Rightarrow 1000=t^2\\\Rightarrow t=\sqrt{1000}\\\Rightarrow t=31.6\ s

Time taken by the cars to meet 31.6 seconds.

5 0
3 years ago
Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 20 cm apart. The sound
Sophie [7]

Answer:

a. Wavelength = λ = 20 cm

b. Next distance of maximum intensity will be 40 cm

Explanation:

a. The distance between the two speakers is 20cm. SInce the intensity is maximum which refers that we have constructive interference and the phase difference must be an even multiple of π and equivalent path difference is nλ.

Now when distance increases upto 30 cm between the speakers, the sound intensity becomes zero which means that there is destructive interference and equivalent path is now increased from nλ to nλ + λ/2.

This we get the equation:

(nλ + λ/2) - nλ = 30-20

λ/2 = 10

λ = 20 cm

b. at what distance, sound intensity will be maximum again.

For next point calculation for maximum sound intensity, the path difference must be increased (n+1) λ. The distance must increase by λ/2 from the point of zero intensity.

= 30 + λ/2

= 30 + 20/2

=30+10

=40 cm

7 0
3 years ago
****PLEASE HELP**** WILL MARK BRAINLIEST
allochka39001 [22]

Answer:

The Current decreases

Explanation:

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4 0
3 years ago
Se coloca una piedra de 600 g en una Honda de 50 cm y se la hace girar a una velocidad de 4 m/s. Dibuja la fuerza que ejerce la
Dima020 [189]

Answer:

Fc = 19.2 N

Explanation:

In this case, the force of the Honda over the rock, is a centripetal force. Then, you have:

F_c=m\frac{v^2}{r}

m: mass of the rock = 600g = 0.6 kg

v: tangential velocity of the Honda = 4m/s

r: radius of the Honda = 50cm = 0.5m

You replace the values of m, r and v in the equation for Fc:

F_c=(0.6kg)\frac{(4m/s)^2}{0.5m}\\\\F_c=19.2N

hence, the force has a magnitude of 19.2 N

If the rock would have more mass the centripetal force would be higher

4 0
3 years ago
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