The radius of the curved road at the given condition is 54.1 m.
The given parameters:
- <em>mass of the car, m = 1000 kg</em>
- <em>speed of the car, v = 50 km/h = 13.89 m/s</em>
- <em>banking angle, θ = 20⁰</em>
The normal force on the car due to banking curve is calculated as follows;

The horizontal force on the car due to the banking curve is calculated as follows;

<em>Divide </em><em>the second equation by the first;</em>

Thus, the radius of the curved road at the given condition is 54.1 m.
Learn more about banking angle here: brainly.com/question/8169892
Answers
The car's forward motion is opposed by the friction between the road and the tires and by the resistance of the air.
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Answer:
Explanation:
A magnet has a magnetic field around it which originates at the north pole and enters through the south pole.
In a magnet, like poles will repel each other and unlike poles will attract.
- The north pole of one magnet will repel another north pole of another magnet.
- North pole of one magnet will attract the south pole of another magnet.
- This is the law of attraction and repulsion of magnet.