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vekshin1
3 years ago
6

Suppose a plane accelerates from rest for 30 s, achieving a takeoff speed of 80 m/s after traveling a distance of 1200 m down th

e runway. A smaller plane with the same acceleration has a takeoff speed of 40 m/s. Starting from rest, after what distance will this smaller plane reach its takeoff speed? Knight, Randall D., (Professor Emeritus). College Physics (p. 64). Pearson Education. Kindle Edition.
Physics
1 answer:
vladimir2022 [97]3 years ago
3 0

Answer:

The distance is 300 m.

Explanation:

Given that,

Time = 30 s

Speed = 80 m/s

Distance = 1200 m

Speed of smaller plane = 40 m/s

We need to calculate the acceleration

Using equation of motion

s= ut+\dfrac{1}{2}at62

Put the value in the equation

1200=0+\dfrac{1}{2}\times a\times(30)^2

a=\dfrac{2\times1200}{30\times30}

a=2.67\ m/s^2

We need to calculate the distance

Using equation of motion

v^2=u^2+2as

Put the value in the equation

40^2=0+2\times2.67\times s

s=\dfrac{40^2}{2\times2.67}

s=299.62\approx 300\ m

Hence, The distance is 300 m.

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