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3 years ago

Which expression correctly represents a balanced reduction half-reaction?

1 answer:

6 0

For answering for the question, there exists four choices:
1) Na+ + e- -------------- Na
2) Na --------Na+ + e-
3) Cl2 + 2e- ------------ Cl-
4) 2Cl- ---------Cl2 + 2e-

reduction half-reaction general formula is
oxidant + e - or + -------- Product

so in our case the answer is
1) Na+ + e- -------------- Na (exactly balanced)

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X^2/2x^5=2 how do you solve this ?

Natasha2012 [34]

Answer:

$x=\sqrt[3]{\frac{1}{4}}$

Explanation:

$\displaystyle\frac{x^2}{2x^5}=2\\\\x^2=4x^5\\\\1=4x^3\\\\x^3=\frac{1}{4}\\\\\\x=\sqrt[3]{\frac{1}{4}}$

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3 years ago

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Write the net ionic equation for the reaction of aqueous solutions of ammonium chloride and iron(III) hydroxide.

vagabundo [1.1K]

Answer:

$Fe(OH)_3(s)\rightarrow Fe^{3+}(aq)+3OH^-(aq)$

Explanation:

Hello.

In this case, for the reaction between aqueous solutions of ammonium chloride and iron (III) hydroxide, we have the following complete molecular reaction:

$3NH_4Cl(aq)+Fe(OH)_3(s)\rightarrow 3NH_4OH+FeCl_3$

And the full ionic equation, taking into account that the iron (III) hydroxide cannot be dissolved as it is insoluble in water:

$3NH_4^+(aq)+3Cl^-(aq)+Fe(OH)_3(s)\rightarrow 3NH_4^+(aq)+3OH^-(aq)+Fe^{3+}(aq)+3Cl^-(aq)$

Finally, the net ionic equation, considering that spectator ions are NH₄⁺, Cl⁻ as they are both the left and right side, therefore, the net ionic equation is:

$Fe(OH)_3(s)\rightarrow Fe^{3+}(aq)+3OH^-(aq)$

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3 years ago

Consider the substances hydrogen (H2), fluorine (F2), and hydrogen fluoride (HF). Based on their molecular structures, how does

katovenus [111]

Answer:

The boiling point of HF is higher than the boiling point of H2, and it is higher than the boiling point of F2.

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In HF, inter- molecule forces will be present between the hydrogen and fluorine atoms. There will be hydrogen bonding present among the hydrogen and fluorine atoms. Hydrogen bonds are strong bonds and hence the boiling point for HF would be high as much energy will be required to break these bonds.

H2 and F2 will only have intra-molecular attractions and there will be no hydrogen bonds present in them. As a result, their boiling point will be lower.

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3 years ago

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