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3 years ago

I NEED THIS ASAP!!! 20 points!

1 answer:

7 0

Gravitational potential energy=mass*gravitational acceleration*heightKinetic energy = 0.5*mass*velocity²Thus:K.E0.5*1*x²=12.5x²=12.5/(0.5*1)x=√12.5/(0.5*1)x=5
GPEmass*gravitational acceleration*height1*9.81*h=98h=98/(9.81*1)h= 9.98 J approximately, rounded 10meters

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3 years ago

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In the figure, a weightlifter's barbell consists of two identical small but dense spherical weights, each of mass 50 kg. These w

kondaur [170]

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Explanation:

The total moment of inertia of the system is the sum of the moment of inertia of the rod + the moment of inertia of the two balls.

The moment of inertia of the rod about its centre is given by

$I_r = \frac{1}{12}ML^2$

where

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Substituting,

$I_r = \frac{1}{12}(24)(0.96)^2=1.84 kg m^2$

The moment of inertia of one ball is given by

$I_b = mr^2$

where

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So we have

$I_b = (50)(0.48)^2=11.5 kg m^2$

Therefore, the total moment of inertia of the system is

$I=I_r + 2I_b = 1.84+ 2(11.5)=24.8 kg m^2$

Learn more about inertia:

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3 years ago

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Rudiy27

Answer:

Explanation:

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Answer:

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