Let denote the position vector of the ball hit by player A. Then this vector has components
where is the magnitude of the acceleration due to gravity. Use the vertical component to find the time at which ball A reaches the ground:
The horizontal position of the ball after 0.49 seconds is
So player B wants to apply a velocity such that the ball travels a distance of about 12 meters from where it is hit. The position vector of the ball hit by player B has
Again, we solve for the time it takes the ball to reach the ground:
After this time, we expect a horizontal displacement of 12 meters, so that satisfies
Answer:
Forms over water, warm humid air mass, it's a polar air mass
Explanation: I think that's right sorry if it's not..
GL! :)
Answer:
C. Talk test
Explanation:
The talk test would be readily available to me at the the least cost.
The talk test is about the easiest way that one can monitor intensity as they exercise. Because the only thing needed here is the ability to talk and to breathe.
The intensity lies on if one can talk and breathe at the same time. The harder one exercises, the more breathless they become and they find it difficult to talk.
The answer would be D) Kinetic friction because kinetic means during and in motion and happening/occurring so since the box is moving now across the floor, its in motion so that's why its D).
Solution :
Given data :
Mass of ice, m = 200 g
Mass of water, M = 500 g
Temperature of ice = 0°C
Temperature of water = 20°C
We known ;
The latent heat of fusion of water is
The specific heat of water, C = 4.18 kJ/kg K
a). Heat required to change the ice into water is :
J
Heat required to cool the warm water is :
From above result,
This means that total ice could not melt.
So, the temperature must be T = 0°C
b). Q' = mL
m = 0.1253 kg
m = 125.3 g
m = 125 g
Therefore, 125 g of ice had melted.