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3 years ago

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Jasmine is late to science class and misses the very beginning of notes for the day. These are Jasmine’s notes: –Round objects t

hat orbit the Sun –Not large enough to have enough gravitational pull to clear the path of their orbit –4 known in the Kuiper Belt (Eris, Haumea, Makemake, and Pluto) –1 in the asteroid belt (Ceres) Jasmine later copied the title of the notes from a friend. What title did Jasmine most likely copy? Comets The Kuiper Belt Asteroids Dwarf Planets

2 answers:

SpyIntel [72]3 years ago

8 0

Answer:

d

Explanation:

sertanlavr [38]3 years ago

5 0

Answer:

D. Dwarf Planets

Explanation:

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which pole of a compass needle points north ? please give simple answer with little explaining if any :)

Mumz [18]

I think the North Pole
If I understand this correctly

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3 years ago

Meteor Infrasound A meteor that explodes in the atmosphere creates infrasound waves that can travel multiple times around the gl

ladessa [460]

Answer:

The frequency of these waves is $4.27\times10^{-2}\ Hz$

Explanation:

Given that,

Wavelength = 6.6 km

Distance = 8810 km

Time t = 8.67 hr

We need to calculate the velocity of sound

Using formula of velocity

$v = \dfrac{D}{T}$

Where, D = distance

T = time

Put the value into the formula

$v =\dfrac{8810}{8.67}$

$v=1016\ km/hr$

We need to calculate the frequency

Using formula of frequency

$v=n\lambda$

$n=\dfrac{v}{\lambda}$

Put the value into the formula

$n=\dfrac{1016}{6.6}$

$n=153.93\ hr$

$n=\dfrac{153.93}{60\times60}$

$n=0.0427\ Hz$

$n=4.27\times10^{-2}\ Hz$

Hence, The frequency of these waves is $4.27\times10^{-2}\ Hz$

8 0

3 years ago

What is the force of impact of a 100 kg diver who falls into a swimming pool and hits the surface of the water and comes to a st

Simora [160]

Answer:

F = 53153.36[N]

Explanation:

In order to solve this problem, we must first use the principle of conservation of energy which is transformed from potential energy to kinetic, in this way we can determine the velocity at which the person enters the water.

$E_{pot}=E_{kin}\\m*g*h=\frac{1}{2}*m*v^{2}$

where:

m = mass = 100 [kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 9 [m]

v = velocity [m/s]

Now replacing we can determinate the velocity.

$v^{2}=2*g*h\\v=\sqrt{2*g*h}\\v=\sqrt{2*9.81*9}\\v = 13.28[m/s]$

Then we can calculate the momentum which can be calculated as the product of force by time, this momentum is also equal to the product of mass by velocity.

$P=m*v\\and\\P =F*t\\F*t=m*v$

Now replacing:

F = impact force [N]

t = time = 0.025 [s]

m = 100 [kg]

v = velocity = 13.28 [m/s]

$F*0.025=100*13.28\\F=53153.36[N]$

8 0

3 years ago

The area on the thermometer marked with the letter A is called the <br> .

makvit [3.9K]

It's called auxiliary scale

4 0

3 years ago

Read 2 more answers

A 50.0 mg sample of an unknown radioactive substance was placed in storage and its mass measured periodically. After 19.7 days,

PilotLPTM [1.2K]

<h2>Answer: 4.928 days </h2><h2 />

Explanation:

This problem can be solved using the <u>Radioactive Half Life Formula: </u>

<u></u>

$A=A_{o}.2^{\frac{-t}{h}}$ (1)

Where:

$A=3.13mg$ is the final amount of the material

$A_{o}=50mg$ is the initial amount of the material

$t=19.7days$ is the time elapsed

$h$ is the half life of the material (the quantity we are asked to find)

Knowing this, let's substitute the values and find $h$ from (1):

$3.13mg=(50mg)2^{\frac{-19.7days}{h}}$ (2)

$\frac{3.13mg}{50mg}=2^{\frac{-19.7days}{h}}$ (3)

Applying natural logarithm in both sides:

$ln(\frac{3.13mg}{50mg})=ln(2^{\frac{-19.7days}{h}})$ (4)

$-2.77=-\frac{19.7days}{h}ln(2)$ (5)

Clearing $h$ :

$h=\frac{-19.7days}{-2.77}(0.693)$ (6)

Finally:

$h=4.928days$

6 0

3 years ago