Ask question

Ask question

All categories

3 years ago

7

The motion of a car on a position-time graph is represented with a horizontal line. What does this indicate about the car's moti

on?
A. It's not moving.
B.
It's moving at a constant speed.
O C. It's moving at a constant velocity.
OD. It's speeding up.

1 answer:

Art [367]3 years ago

7 0

Answer:

B

Explanation:

on USAtestprep

You might be interested in

A car is moving at a constant speed of 14 m/s when the driver presses down on the gas pedal and accelerates for 14 s with an acc

Vinil7 [7]

acceleration of car is 1.8 m/s^2

time = 14 s

initial speed = 14 m/s

so the final speed is calculated by

$v_f = v_i + at$

$v_f = 14 + 14 * 1.8$

$v_f = 39.2 m/s$

so the total distance moved in this interval of time is

$d = \frac{v_f + v_i}{2}* t$

$d = \frac{39.2 + 14}{2}* 14$

$d = 372.4 m$

now the average speed is given as

$v = \frac{d}{t}$

$v = \frac{372.4}{14}$

$v = 26.6 m/s$

so the average speed will be 26.6 m/s

7 0

3 years ago

A light spring obeys Hooke's law. The spring's unstretched length is 34.0 cm. One end of the spring is attached to the top of a

maxonik [38]

Answer:

Explanation:

Hooke's law is represented by thee formula

F = ke where F is force in N and K is the spring constant.

Initial length of the spring = 34cm = 0.34 m

mass of 7.00kg hung

weight = mg = 7 × 9.8 = 68.6 N

Final length of the spring = 44.5 cm = 0.445 m

extension = final length - initial length = 0.445 m - 0.34 m = 0.105 m

a) F = Ke

K = F / e = 68.6 N /0.105 m = 653.33 N/m = 0.653 kN/m

b) F = 150 N

k = 653.33 N/m

F = ke

150 N / 653.33 N/m = e

e = 0.23 m

new length = 0.34 + 0.23= 0.57 m = 57 cm

5 0

3 years ago

Explain why a clothes iron with a metal base must be connected to the mains by a three-core cable.

Lapatulllka [165]

The charge going to the clothes iron needs to be grounded so the iron does not make any shock

3 0

3 years ago

A rocket with a mass of 2.0 Ã 106 kg is designed to take off from the surface of the earth by burning fuel and ejecting it with

julsineya [31]

thrust force getting from the burning of mass should balance the weight of the rocket

here thrust force is given as

$F_t = v\frac{dm}{dt}$

now by force balance we can say

$mg = v \frac{dm}{dt}$

now plug in all values in this

$(2 \times 10^6)(9.8) = 3500 \times \frac{dm}{dt}$

$\frac{dm}{dt} = \frac{19.6 \times 10^6}{3500}$

$\frac{dm}{dt} = 5600 kg/s$

so rate of mass burning per second will be 5600 kg per second in order to lift up the rocket

6 0

3 years ago

Whats a transverse wave?

Mazyrski [523]

Answer:

a wave vibrating at right angles to the direction of its propagation.

Explanation:

7 0

3 years ago