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Stels [109]
1 year ago
10

A toy doll and a toy robot are standing on a frictionless surface facing each other. The doll has a mass of 0. 20 kg, and the ro

bot has a mass of 0. 30 kg. The robot pushes on the doll with a force of 0. 30 n. The magnitude of the acceleration of the robot is.
Physics
1 answer:
diamong [38]1 year ago
8 0

The acceleration of the robot is 1.43 m/s2 in magnitude.

<h3>What is acceleration?</h3>

The acceleration of an object is defined as the variation of the velocity with respect to time. The acceleration is calculated by finding the ratio of the change in velocity to the change in time.

The acceleration is also calculated by using the force formula. The force is actually defined as the acceleration produced in the body by applying the force on an object of mass m.

On a non-stick surface, a toy robot and doll are standing side by side. The robot weighs 0. 30 kg, while the doll weighs 0. 20 kg. With a force of 0. 30 n, the robot pushes against the doll.

According to Newton's second law.

F = mass x acceleration

Given that

Force applied = 1N

Acceleration = Force/mass

Substitute the values and get acceleration.

Acceleration = 1/0.7

Acceleration = 1.43m/s²

Hence, the acceleration of the robot is 1.43 m/s2 in magnitude.

To know more about acceleration follow

brainly.com/question/141388

#SPJ4

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Explanation:

Here, we use the law of conservation of momentum, as follows:

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