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Stels [109]
1 year ago
10

A toy doll and a toy robot are standing on a frictionless surface facing each other. The doll has a mass of 0. 20 kg, and the ro

bot has a mass of 0. 30 kg. The robot pushes on the doll with a force of 0. 30 n. The magnitude of the acceleration of the robot is.
Physics
1 answer:
diamong [38]1 year ago
8 0

The acceleration of the robot is 1.43 m/s2 in magnitude.

<h3>What is acceleration?</h3>

The acceleration of an object is defined as the variation of the velocity with respect to time. The acceleration is calculated by finding the ratio of the change in velocity to the change in time.

The acceleration is also calculated by using the force formula. The force is actually defined as the acceleration produced in the body by applying the force on an object of mass m.

On a non-stick surface, a toy robot and doll are standing side by side. The robot weighs 0. 30 kg, while the doll weighs 0. 20 kg. With a force of 0. 30 n, the robot pushes against the doll.

According to Newton's second law.

F = mass x acceleration

Given that

Force applied = 1N

Acceleration = Force/mass

Substitute the values and get acceleration.

Acceleration = 1/0.7

Acceleration = 1.43m/s²

Hence, the acceleration of the robot is 1.43 m/s2 in magnitude.

To know more about acceleration follow

brainly.com/question/141388

#SPJ4

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azamat

The wavelengths of the constituent travelling waves CANNOT be 400 cm.

The given parameters:

  • <em>Length of the string, L = 100 cm</em>

<em />

The wavelengths of the constituent travelling waves is calculated as follows;

L = \frac{n \lambda}{2} \\\\n\lambda = 2L\\\\\lambda = \frac{2L}{n}

for first mode: n = 1

\lambda = \frac{2\times 100 \ cm}{1} \\\\\lambda = 200 \ cm

for second mode: n = 2

\lambda = \frac{2L}{2} = L = 100 \ cm

For the third mode: n = 3

\lambda = \frac{2L}{3} \\\\\lambda = \frac{2 \times 100}{3} = 67 \ cm

For fourth mode: n = 4

\lambda = \frac{2L}{4} \\\\\lambda = \frac{2 \times 100}{4} = 50  \ cm

Thus, we can conclude that, the wavelengths of the constituent travelling waves CANNOT be 400 cm.

The complete question is below:

A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent travelling waves CANNOT be:

A. 400 cm

B. 200 cm

C. 100 cm

D. 67 cm

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How many moles of He atoms are in 6.00 g of He?
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Joe is trying to soup up his dragster. He knows that the time needed for the car to go from 0 to 100 miles per hour varies inver
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Translating the first sentence into equation we get, t = k(1/h) where t is time in seconds, k is the constant and h is the horsepower. Substituting the values in the equation we have, 12s = k(1/200) we have a k = 2400 seconds – hp. To get the time at 240 hp we use the equation above and the constant, we get, t = (2400 seconds-hp)(1/240hp) t = 10seconds.

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For a distant astronomical object (a quasar) is moving away from us at half the speed of light, the speed of the light we receive from this quasar  is mathematically given as c = 3x108 m/s

<h3>What is the speed of light?</h3>

Generally, the equation for the   is mathematically given as

The speed of light can be said to be measured to be approximately the value c = 3x108 m/s

.

In conclusion, An will not influence  3x108 m/s unless both are inertia and frames refrences where newtons laws are valid, so the speed of light measured from the earth frame is equal to  3x108 m/s

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