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Sphinxa [80]
3 years ago
10

Which element is most likely to be shiny?

Physics
2 answers:
mestny [16]3 years ago
5 0

Answer:

Calcium, or as we intellectuals call it, Bone Juice

Explanation:

stellarik [79]3 years ago
4 0

calcium (ca) is most likely to be shiny

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Heat engines are less than 100% efficient because absolute zero cannot be reached
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Ross training for a half marathon which is 13.1 miles long. Within four months he has progressed to an 11 mile practice run if R
damaskus [11]

If Ross takes two months off from training, his fitness level will reduce in comparison to what it was two months ago.

  • In as little as 3–4 weeks after beginning strength training, Ross will probably experience weight increase, energy loss, diminished balance, diminished strength (making it tougher to carry out daily tasks), and overall fewer fitness levels.
  • Many people mistakenly believe they lose muscle mass far more quickly than they actually do because their muscles' ability to store water and glycogen is declining.
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learn more about fitness here: brainly.com/question/13490156

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4 0
2 years ago
Please help meeeee!!!!!!
Vinil7 [7]

Answer:

Net force

Explanation:

Bruh, easy question

3 0
2 years ago
Why doesnt food have energy
Nataly_w [17]
Food has calories which feeds your bones in your body from eating away your muscles, it doesn’t have “energy” on the other hand pop and drinks do.
3 0
3 years ago
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A 75-g bullet is fired from a rifle having a barrel 0.540 m long. Choose the origin to be at the location where the bullet begin
Mashutka [201]

The given question is incomplete. The complete question is as follows.

A 75-g bullet is fired from a rifle having a barrel 0.540 m long. Choose the origin to be at the location where the bullet begins to move. Then the force (in newtons) exerted by the expanding gas on the bullet is 14,000 + 10,000x − 26,000x^{2}, where x is in meters. Determine the work done by the gas on the bullet as the bullet travels the length of the barrel.

Explanation:

We will calculate the work done as follows.

     W = \int_{0}^{0.54} F dx

         = \int_{0}^{0.54} (14,000 + 10,000x - 26,000x^{2}) dx

         = [14000x + 5000x^{2} - 8666.7x^{3}]^{0.54}_{0}

         = 7560 + 1458 - 1364.69

         = 7653.31 J

or,      = 7.65 kJ       (as 1 kJ = 1000 J)

Thus, we can conclude that the work done by the gas on the bullet as the bullet travels the length of the barrel is 7.65 kJ.

5 0
3 years ago
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