Answer:
7.17 g/mL
Explanation:
Density = Mass / Volume
Given mass of object : 80.4g
We are not given the objects volume, however we are given that when put inside of a container with 20.0mL water, the level of the water rises to 31.2 mL.
31.2 - 20 = 11.2
The water level rose 11.2 mL when the object was placed inside of the cylinder containing the water therefore the object has a volume of 11.2mL
Now to find it's density
recall that density = mass / volume
mass = 80.4 and volume = 11.2mL
so density = 80.4/11.2 = 7.17 g/mL
Answer:
Empirical formula: BH3
Molecular Formula: B2H6
Explanation:
To solve the exercise, we need to know how many boron atoms and how many hydrogen atoms the compound has. We know that of the total weight of the compound, 78.14% correspond to boron and 21.86% to hydrogen. As the weight of the compound is between 27 g and 28 g, using the above percentages we can solve that the compound has between 21.1 g and 21.8 g of boron, and between 5.9 g and 6.1 g of hydrogen:
100% _____ 27 g
78.14% _____ x = 78.14% * 27g / 100% = 21.1 g boron
100% ______27 g
21.86% ______ x = 21.86% * 27g / 100% = 5.9 g hydrogen
100% _____ 28 g
78.14% _____ x = 78.14% * 28g / 100% = 21.8 g boron
100% _____ 28g
21.86% _____ x = 21.86% * 28g / 100% = 6.1 g hydrogen
So, if the atomic weight of boron is 10.8 g, there must be two boron atoms in the compound that sum 21.6 g. The weight of hydrogen is 1 g, so the compound must have six hydrogen atoms.
The molecular formula represents the real amount of atoms that form a compound. Therefore, the molecular formula of the compound is B2H6.
The empirical formula is the minimum expression that represents the proportion of atoms in a compound. For example, ethane has 2 carbon atoms and 6 hydrogen atoms, so its molecular formula is C2H6, however, its empirical formula is CH3. Therefore, the empirical formula of the boron compound is BH3.
My Choice will be the sample C with a coefficient of absorption 62 % and the reason is that the percentage of the energy in an incident wave that remains in a reflected wave from this material is the smallest. Because this sample has the highest percentage of the coefficient of absorption than the other samples, As the sound Absorption coefficient is a part of the sound energy that absorbed by a material.And Its value varies with the angles of incident and frequency. So sample C is the best to be used as a soundproof room.
