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Lilit [14]
3 years ago
11

If I pour Sodium Hydroxide to Copper Sulfate, would this be a physical or chemical change?

Chemistry
2 answers:
sp2606 [1]3 years ago
7 0
Hey there!

It would be a chemical change because a new substance was formed.

Hope it helped!
gizmo_the_mogwai [7]3 years ago
5 0
It would be a chemical change.
Hope this helps!
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Why the ph of glycine increases when 0.1 M NaOH is added dropwise​
shtirl [24]

Answer:

The acid-base reaction produces glycine reduction, and hence the increase of glycine pH.

Explanation:

The glycine is an amino acid with the following chemical formula:

NH₂CH₂COOH  

The COOH functional group is what gives the acid properties in the molecule.      

Hence, when NaOH is added to glycine an acid-base reaction takes place in which COOH reacts with the NaOH added:

NH₂CH₂COOH + OH⁻ ⇄ NH₂CH₂COO⁻ + H₂O

The glycine concentration starts to shift to its ion form (NH₂CH₂COO⁻) because of the reaction with NaOH, that is why the pH glycine increases when NaOH is added.  

Therefore, the acid-base reaction produces glycine reduction, and hence the increase of glycine pH.  

I hope it helps you!  

7 0
3 years ago
Gold has a specific heat of 0.126 J/g.C. Copper has a specific heat of 0.386 J/g C. Which of the two metals would require more
ASHA 777 [7]

Answer:

The copper, because its specific heat is higher, meaning it takes more heat (Joules) per gram to raise the temperature 1 degree Celsius.

Explanation:

8 0
3 years ago
To what volume in millimeters must 50.0 mL of 18.0 M H2SO4 be diluted to obtain 4.35 M H2SO4?
poizon [28]
We know that to relate solutions of with the factors of molarity and volume, we can use the equation: M_{1}  V_{1} = M_{2}  V_{2}

**NOTE: The volume as indicated in this question is defined in L, not mL, so that conversion must be made. However it is 1000 mL = 1 L.

So now we can assign values to these variables. Let us say that the 18 M H_{2}  SO_{4} is the left side of the equation. Then we have:

(18 M)(0.050 L)=(4.35M) V_{2}

We can then solve for V_{2}:

V_{2}= \frac{(18M)(0.05L)}{4.35M} and V_{2} =0.21 L or 210 mL

We now know that the total amount of volume of the 4.35 M solution will be 210 mL. This is assuming that the entirety of the 50 mL of 18 M is used and the rest (160 mL) of water is then added.


7 0
4 years ago
Determine the volume of an object that has a mass of 455.6 g and a density of 19.3 g/cm3. (1cm3 = 1ml) select one:
Dmitry [639]
The answer is B. The density, or more precisely, the volumetric mass density, of a substance is its mass per unit volume.

4 0
3 years ago
Which of the following solutions would have the highest osmotic pressure?
Gennadij [26K]

Answer:

Option d. 0.10 m Cr₂(SO₄)₃

Explanation:

Formula for the osmotic pressure is determined as:

π = M . R . T . i

So you have to take account the i (Van't Hoff factor, numbers of ions dissolved)

  • CH₄N₂O → 0.35 m

Urea is an organic compound, so the i value is 1

  • H₂O → The i is also 1
  • Zn(CH₃COO)₂ → 0.15 m

Zync acetate can be dissociated:

Zn(CH₃COO)₂  →  1Zn²⁺  + 2CH₃COO⁻

In this case, the i is 3. (you see, the stoichiometry of ions)

Cr₂(SO₄)₃ →  0.10 m

Chromium sulfate is dissociated:

Cr₂(SO₄)₃ →  2Cr³⁺  +  3SO₄⁻²

i = 5

BaI₂ → 0.16 m

BaI₂ →  1Ba²⁺  +  2I⁻

i = 3

8 0
3 years ago
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