Answer:
9 × 10⁻³ mol·L⁻¹s⁻¹
Explanation:
Data:
k = 1 × 10⁻³ L·mol⁻¹s⁻¹
[A] = 3 mol·L⁻¹
Calculation:
rate = k[A]² = 1 × 10⁻³ L·mol⁻¹s⁻¹ × (3 mol·L⁻¹)² = 9 × 10⁻³ mol·L⁻¹s⁻¹
Answer:
3 atoms
Explanation:
it contains 2 atoms of hydrogen(H) and 1 atom of oxygen(O). So in total there are 3 atoms.
We calculate the molar concentration [Cl⁻] using stoichiometry. MnCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of MnCl2 that dissolves.
MnCl2(s) --> Mn+(aq) + 2 Cl⁻(aq)
[Cl⁻] = 0.68 mol MnCl2/1L × 2 mol Cl⁻ / 1 mol MnCl2 = 1.4 M
The answer to this question is [Cl⁻] = 1.4 M
Answer:
Mass = 5.24 g
Explanation:
Given data:
Number of atoms of Ca = 7.9×10²² atoms
Mass of Ca = ?
Solution:
First of all we will calculate the number of moles by using Avogadro number.
1 mole contain 6.022×10²³ atoms
7.9×10²² atoms × 1 mol /6.022×10²³ atoms
1.31 ×10⁻¹ mol
0.131 mol
Mass of Ca:
Mass = number of moles × molar mass
Mass = 0.131 mol × 40 g/mol
Mass = 5.24 g
