At the same temperature and pressure, 1.00 moles of H2 gas occupies
2 answers:
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The mixture flow rate in lbm/h = 117.65 lbm/h
<h3>Further explanation</h3>Given
15.0 wt% methanol
The flow rate of the methyl acetate :100 lbm/h
Required
the mixture flow rate in lbm/h
Solution
mass of methanol(CH₃OH, Mw= 32 kg/kmol) in mixture :
mass of the methyl acetate(C₃H₆O₂,MW=74 kg/kmol,85% wt) in 200 kg :
Flow rate of the methyl acetate in the mixture is to be 100 lbm/h.
1 kg mixture = 0.85 .methyl acetate
So flow rate for mixture :
Answer: 4.2
Explanation:
