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masya89 [10]
3 years ago
7

Describe the modern system of classification. Help please!

Chemistry
2 answers:
alina1380 [7]3 years ago
8 0

Answer:

The modern system of classification is a hierarchy with eight levels. These levels are domain, kingdom, phylum, class, order, family, genus, and species. There are three domains and six kingdoms in the modern system.

Explanation:

DENIUS [597]3 years ago
7 0

Answer:

its called TAXON0MY

Explanation:

they are classified in eight steps namely doma!n, k!ngdom, phylum, class, order, family, genus, and spec!es

but sometimes we do not include doma!n

if you want to name an organism you use both the genus group and the spec!es group

Example:

The scientific name for humans like us is h0m0 sap!ens

H0m0- This is our genus group

sap!ens- This is our spec!es group

sorry for using the exclamation mark it means i

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Attempt 4 A galvanic cell has an X electrode with X 2 plus ions in the left beaker and a Y electrode with Y 2 plus ions in the r
babymother [125]

Answer:

See explaination

Explanation:

Since X is more reactive than Y

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Overall cell reaction is:

X(s) + Y2+(aq) => X2+(aq) + Y(s)

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4 0
3 years ago
If we use 18 moles of H2 how many moles of H2O do we make? Use this chemical equation: 6H2 + O2 → 3H2O
Ilya [14]
<h3>Answer:</h3>

9 mol H₂O

<h3>General Formulas and Concepts:</h3>

<u>Math</u>  

<u>Pre-Algebra</u>  

Order of Operations: BPEMDAS  

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>  

<u>Atomic Structure</u>  

  • Reading a Periodic Table
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>  

  • Using Dimensional Analysis
  • Analyzing reactions RxN
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 6H₂ + O₂ → 3H₂O

[Given] 18 mol H₂

[Solve] mol H₂O

<u>Step 2: Identify Conversions</u>

[RxN] 6 mol H₂ → 3 mol H₂O

<u>Step 3: Stoich</u>

  1. [DA] Set up conversion:                                                                               \displaystyle 18 \ mol \ H_2(\frac{3 \ mol \ H_2O}{6 \ mol \ H_2})
  2. [DA] Simplify:                                                                                                 \displaystyle 18 \ mol \ H_2(\frac{1 \ mol \ H_2O}{2 \ mol \ H_2})
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3 0
3 years ago
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3 years ago
When FeC13 is ignited in an atmosphere of pure oxygen, this reaction takes place. 4FeCl3(sJ 30lgJ ~ 2F~0 (sJ 6Cl2(gJ If 3.00 mol
oksano4ka [1.4K]

Answer : The reagent present in excess and remains unreacted is, O_2

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Moles of FeCl_3 = 3.00 mole

Moles of O_2 = 2.00 mole

Excess reagent : It is defined as the reactants not completely used up in the reaction.

Limiting reagent : It is defined as the reactants completely used up in the reaction.

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

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From the balanced reaction we conclude that

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So, 3.00 moles of FeCl_3 react with \frac{3.00}{2}=1.5 moles of O_2

From this we conclude that, O_2 is an excess reagent because the given moles are greater than the required moles and FeCl_3 is a limiting reagent and it limits the formation of product.

Hence, the reagent present in excess and remains unreacted is, O_2

4 0
3 years ago
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s2008m [1.1K]
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