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VashaNatasha [74]
3 years ago
13

Which half-reaction equation represents the

Chemistry
2 answers:
erica [24]3 years ago
8 0
The reduction reaction is the gain of electrons while oxidation reaction is the loss of electrons. For potassium ion(K+), the reaction should be K+ + e- ==> K. So the answer is (1).
GalinKa [24]3 years ago
4 0

Answer : The correct option is, (1) K^++e^-\rightarrow K

Explanation :

Oxidation-reduction reaction : It is a type of reaction where the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is a reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

As per question, the half-reaction equation of reduction of a potassium ion will be :

K^++e^-\rightarrow K

In this reaction, the oxidation state of potassium changes from (+1) to (0) that means the oxidation state decreases. So, this reaction shows the half-reaction equation of reduction of a potassium ion.

Therefore, the correct option is, (1) K^++e^-\rightarrow K

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A mixture of methane and air is capable of being ignited only if the mole percent of methane is between 5% and 15%. A mixture co
DaniilM [7]

Answer:

Explanation:

The air 9% mole% methane have an average molecular weight of:

9%×16,04g/mol + 91%×29g/mol = 27,8g/mol

And a flow of 700000g/h÷27,8g/mol = 25180 mol/h

In the reactor where methane solution and air are mixed:

In = Out

Air balance:

91% air×25180 mol/h + 100% air×X = 95%air×(X+25180)

Where X is the flow rate of air in mol/h = <em>20144 mol air/h</em>

<em></em>

The air in the product gas is

95%×(20144 + 25180) mol/h = 43058 mol air× 21%O₂ = 9042 mol O₂ ×32g/mol = <em>289 kg O₂</em>

43058 mol air×29g/mol <em>1249 kg air</em>

Percent of oxygen is: \frac{289kg}{1249 kg} =<em>0,231 kg O₂/ kg air</em>

<em></em>

I hope it helps!

4 0
3 years ago
When the equal molar amounts of of both the acid and the base were reacts, what happened in the reaction?
Advocard [28]
It is going to be reaction of neutralization, and water and salt will be formed. If acid and base are strong, the reaction of the solution should become neutral.
3 0
4 years ago
Which element is least metallic?<br><br> zinc<br> iron<br> cadmium<br> silver
skad [1K]
Cadmium is less metalic
5 0
3 years ago
Read 2 more answers
Determine the nuclear composition (number of protons and neutrons) of the following isotopes. (a) chromium-52 protons neutrons (
madreJ [45]

Answer: a) chromium-52 :  protons = 24, neutrons = 28

selenium - 80 :  protons = 34, neutrons = 46

molybdenum-98:  protons = 42, neutrons = 56

xenon-132:  protons = 54, neutrons = 78

ytterbium-174 :  protons = 70, neutrons = 104

Explanation:

Atomic number : It is defined as the number of electrons or number of protons present in a neutral atom.

Thus, number of protons = atomic number

Mass number is the number of the entities present in the nucleus which is the equal to the sum of the number of protons and electrons.

Mass number = Number of protons + Number of neutrons

a) chromium-52 :

Atomic number of Chromium is 24 hence number of protons  = 24

52= 24+ Number of neutrons

Number of neutrons = 28

b) selenium - 80 :

Atomic number of selenium is 34 hence number of protons  = 34

80 =  34 +  Number of neutrons

Number of neutrons = 46

c) molybdenum - 98 :

Atomic number of molybdenum is 42 is  hence number of protons  = 42

98 =  42 +  Number of neutrons

Number of neutrons = 56

d) xenon-132:

Atomic number of xenon is 54 hence number of protons  = 54

132 =  54 +  Number of neutrons

Number of neutrons = 78

e) ytterbium-174:

Atomic number of ytterbium is 70 and  hence number of protons  = 70

174 = 70 +  Number of neutrons

Number of neutrons = 104

6 0
3 years ago
Rank the ions in each set in order of decreasing size, and explain your ranking:
Valentin [98]

Answer:

a) Se²⁻> S²⁻ > O²

b) Te²⁻ > I- >Cs+

c)  Cs+ > Ba²⁺ > Sr²⁺

Explanation:

(a) Se²⁻, S²⁻, O²⁻

In general, ionic radius decreases with increasing positive charge.

As the charge on the ion becomes more positive, there are fewer electrons.

The ion has a smaller radius. In general, ionic radius increases with increasing negative charge.

For ions of the same charge (e.g. in the same group) the size increases as we go down a group in the periodic table

Se²⁻> S²⁻ > O²

(b) Te²⁻, Cs⁺, I⁻

Te²⁻ > I- >Cs+

Te2- hast the biggest size, because of the double negative charge.

Cs+ has the smallest size since it has the most positive charge, compared to Te2- and I-.

(c) Sr²⁺, Ba²⁺, Cs⁺

Cs+ > Ba²⁺ > Sr²⁺

Cs+ has the biggest size, because its more downward (compared to Sr2+) and more to the left (compared) ot Ba2+.

Sr2+ has the smallest size because it's more upwords (compared to Cs+ and Ba2+)

5 0
3 years ago
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