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3 years ago

Which sequence isn’t a geometric progression? 2, 6, 18, 54 1, 5, 25, 125 3, 6, 9, 12 or 4, 8, 16, 32?

Mathematics

2 answers:

astra-53 [7]3 years ago

7 0

Answer:

25, 125 3, 6, 9, 12 or 4, 8, 16 is the correct answer.

Step-by-step explanation:

Geometric progression is also known as geometric sequence and it is a sequence of numbers where each term after the initial one is found by multiplying it by a commom ratio, which is a fixed, non-zero number.

The first sequence has 3 as the common ratio. The second one has 5 and the last one, 2. Option 3 doesn not have one, so it is the correct answer.

AlexFokin [52]3 years ago

6 0

Answer:

Step-by-step explanation:

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How to solve this step by step

Paha777 [63]

Yo has to factor since we assume that
if you have xy=0, x and y=0

7n^2-48n+36=0
trial and error
(7n-6)(n-6)=0

set each to zero
7n-6=0
add 6
7n=6
divide 7
n=6/7

n-6=0
add 6
n=6

n=6/7 or 6

8 0

3 years ago

You are in charge of the Annual Powder Puff football game. You designed a t-shirt to sell during the event. A company charges $7

vekshin1

We're looking for C(h), where h is the hundreds of shirts. The fact that they cost "$500 for each additional 100 t-shirt" tells us the slope is 500. Knowing that 1 hundred costs 750, we could use point-slope at this point: (C - 750)/(h - 1) = 500C - 750 = 500h - 500C(h) = 500h + 250 We can check that C(1) = 750 and C(2) = 1250, as we expect. I'll leave it to you to evaluate C(5).

7 0

3 years ago

The linear equation y = 32x + 240 models the relationship between the value of an investment stock, y, and the number of years i

goldfiish [28.3K]

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8 0

3 years ago

write and solve an equation to show thw average number of calendars her 3rd period class sold peer week during the four week cha

kari74 [83]

If they sold 89 calendars over 4 weeks, the 'equation' would look like (x = average calendars sold over 4 weeks):
$x = \frac{89}{4}$

If you solve it, you get:
$22 \frac{1}{4}$

Which is equal to 22.25. Hope this helps!

5 0

3 years ago

g Use this to find the equation of the tangent line to the parabola y = 2 x 2 − 7 x + 6 at the point ( 4 , 10 ) . The equation o

natali 33 [55]

Answer:

The tangent line to the given curve at the given point is $y=9x-26$ .

Step-by-step explanation:

To find the slope of the tangent line we to compute the derivative of $y=2x^2-7x+6$ and then evaluate it for $x=4$ .

$(y=2x^2-7x+6)'$ Differentiate the equation.

$(y)'=(2x^2-7x+6)'$ Differentiate both sides.

$y'=(2x^2)'-(7x)'+(6)'$ Sum/Difference rule applied: $(f(x)\pmg(x))'=f'(x)\pm g'(x)$

$y'=2(x^2)'-7(x)'+(6)'$ Constant multiple rule applied: $(cf)'=c(f)'$

$y'2(2x)-7(1)+(6)'$ Applied power rule: $(x^n)'=nx^{n-1}$

$y'=4x-7+0$ Simplifying and apply constant rule: $(c)'=0$

$y'=4x-7$ Simplify.

Evaluate y' for x=4:

$y'=4(4)-7$

$y'=16-7$

$y'=9$ is the slope of the tangent line.

Point slope form of a line is:

$y-y_1=m(x-x_1)$

where $m$ is the slope and $(x_1,y_1)$ is a point on the line.

Insert 9 for $m$ and (4,10) for $(x_1,y_1)$ :

$y-10=9(x-4)$

The intended form is $y=mx+b$ which means we are going need to distribute and solve for $y$ .

Distribute:

$y-10=9x-36$

Add 10 on both sides:

$y=9x-26$

The tangent line to the given curve at the given point is $y=9x-26$ .

------------Formal Definition of Derivative----------------

The following limit will give us the derivative of the function $f(x)=2x^2-7x+6$ at $x=4$ (the slope of the tangent line at $x=4$ ):

$\lim_{x \rightarrow 4}\frac{f(x)-f(4)}{x-4}$

$\lim_{x \rightarrow 4}\frac{2x^2-7x+6-10}{x-4}$ We are given f(4)=10.

$\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}$

Let's see if we can factor the top so we can cancel a pair of common factors from top and bottom to get rid of the x-4 on bottom:

$2x^2-7x-4=(x-4)(2x+1)$

Let's check this with FOIL:

First: $x(2x)=2x^2$

Outer: $x(1)=x$

Inner: $(-4)(2x)=-8x$

Last: $-4(1)=-4$

---------------------------------Add!

$2x^2-7x-4$

So the numerator and the denominator do contain a common factor.

This means we have this so far in the simplifying of the above limit:

$\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}$

$\lim_{x \rightarrow 4}\frac{(x-4)(2x+1)}{x-4}$

$\lim_{x \rightarrow 4}(2x+1)$

Now we get to replace x with 4 since we have no division by 0 to worry about:

2(4)+1=8+1=9.

6 0

4 years ago