For the fulcrum to balance, the product of weight and distance on both sides of the fulcrum must be the same.
Let d1= x. since total distance is 12, we can write d2 = 12 - x
for the fulcrum to balance:
60x = 50(12 - x)
60x = 600 - 50x
110x = 600
x = 5.45
Thus, d1= 5.45
and
d2= 12 - d1 = 12 - 5.45 = 6.55
d1 = 5.45
d2 = 6.55
To add/subtract fractions you need to have a common denominator...
(2/2)(4n/15)+(5/5)(n/6)
8n/30+5n/30
(8n+5n)/30
13n/30
Answer:
Hello! Your answer is, A) The arrow pointing to the right
Step-by-step explanation:
Hope I helped! Ask me anything if you have any questions! Brainiest plz! Hope you make an 100% and have a wonderful day! -Amelia♥
The solution for this problem would be:
f'(x) = 1 - 1/x^2 = (x^2 - 1)/x^2
is positive where |x| > 1
hence (-inf, -1) and (1, inf) are the regions in which f' is positive and therefore f is increasing.
Therefore, the answer is (-infinity,-1] U [1,infinity).
Notice the picture below
x = 1 and y = -1
now... recall your SOH CAH TOA
now.. what's the value for "r" or the radius? well, using the pythagorean theorem
