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White raven [17]
3 years ago
15

What is the resistance for resistor #2? (must include unit - ohms)

Physics
1 answer:
ser-zykov [4K]3 years ago
3 0

Answer:

10ohms

Explanation:25 minus 10 is 15

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A golf ball flies through the air after being struck with a golf club. Which of the following statements describes the force on
valentina_108 [34]

Answer:

C) The force experienced by the ball equals the force experienced by the club.

Explanation:

When the golfer strikes the ball with his club, the club exerts a force on the ball. Due to Newton's Third Law Of Motion [Every Action has an equal and opposite reaction], the ball also exerts an equal force on the club. However,

As the mass of the club is usually greater than the mass of the ball, it accelerates slower; While the ball way faster, following the equation : F=ma

3 0
3 years ago
Consider the reaction.
BaLLatris [955]

Answer:

Explanation:

Consider the reaction.A(g)↽−−⇀Z(g)A

A

(

g

)

↽

−

−

⇀

Z

(

g

)

The equilibrium constant,

K

, expresses the relationship between the concentrations of the species at equilibrium.

(g)

The energy of A-A bond in A is 98 kJ/mol. The energy of Z-Z bond in Z is 165 kJ/mol. Which statement about the reaction is correct?

1) The activation energy for the forward reaction, Reaction ↽−+X(g)AX(g), is smaller than the activation energy for the reverse reaction, Reaction ⇀+AX(g)↽−.

2) The amount of energy released when A and Z combine to form AX will be greater than the total energy needed to break both A-A and Z-Z bonds (above).

3) The amount of energy released when A and Z combine to form AX will be less than the total energy needed to break both A-A and Z-Z bonds.

4) The activation energy for the forward reaction, Reaction ↽−+X(g)AX(g), is greater than the activation energy for the reverse reaction, Reaction ⇀+AX(g)↽−.

5) The energy of A-A bond in A is greater than the energy of Z-Z bond in Z.

1) The activation energy for the forward reaction, Reaction ↽−+X(g)AX(g), is smaller than the activation energy for the reverse reaction, Reaction ⇀+AX(g)↽−.

It is correct that the activation energy for Reaction ↽−+X(g)AX(g) is smaller than that for Reaction ⇀+AX(g)↽−, because AX is less stable than A or Z, so it takes less energy to break the weaker bond in AX.

2) The amount of energy released when A and Z combine to form AX will be greater than the total energy needed to break both A-A and Z-Z bonds (above).

3) The amount of energy released when A and Z combine to form AX will be less than the total energy needed to break both A-A and Z-Z bonds.

Option (2) is incorrect because, though the formation of AX requires energy, which is not needed for the formation of A or Z; however, the total energy required to break both A-A and Z-Z bonds (above) is more than the amount released when A and Z combine to form AX.

Option (3) is incorrect because the amount of energy released when A and Z combine to form AX will be greater than the total energy needed to break both A-A and Z-Z bonds (above).

4) The activation energy for the forward reaction, Reaction ↽−+X(g)AX(g), is greater than the activation energy for the reverse reaction, Reaction ⇀+AX(g)↽−.

8 0
3 years ago
A heat engine with 0.500 mol of a monatomic ideal gas initially fills a 1000 cm3 cylinder at 700 K . The gas goes through the fo
Zarrin [17]

Answer:

2234.63

Explanation:

Work done per cycle by the engine is calculated as;

W=\int p \ dv

#Since volume doesn't change in the isochoric steps, there is no work done, hence:

W_2=W_3=0

#For an isothermal change of state(ideal gas):

pV=nRT\\\\W=P_iV_ i\int \frac{1}{V} \ dV\\\\=P_iV_ iIn(V_f/V_i)

#for the expansion process:

W_i=0.5mol\times8.3145J/molK\times 700K \ In(6000cm^3/1000cm^3)\\\\W_i=5214.15J

W_4=0.5mol\times8.3145J/molK\times 400K \ In(6000cm^3/1000cm^3)\\\\W_4=-2979.52

W=W_1+W_2+W_3+W_4\\\\=5214.15J-2979.52\\\\=2234.63J

Hence, the engine does 2234.63J per second.

8 0
4 years ago
PLEASE HELP ASAP! i will really appreciate it
Setler79 [48]
What you’re doing is so easy pay attention more I think
4 0
3 years ago
How can oxygen enter the lungs?
Oksanka [162]
I just got this question not to long ago but to answer your question the primary function of the respiratory system is to exchange oxygen<span> and carbon dioxide. Inhaled </span>oxygen enters the lungs<span> and reaches the alveoli. </span>Oxygen<span> passes quickly through this air-blood barrier into the blood in the capillaries. Similarly, carbon dioxide passes from the blood into the alveoli and is then exhaled.</span>
6 0
4 years ago
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