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3 years ago

A chemist needs to order an element that will not react with any other element. Which element should he order

Physics

1 answer:

Gwar [14]3 years ago

4 0

Answer:

Helium

Explanation:

Helium is the least reactive element, since it is a noble gas with the smallest amount of valence rings.

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Why are some consolation visible to New York State observers at midnight during April , but not visible at midnight during Octob

Svetach [21]

"Midnight" means looking away from the Sun. But in 6 months from April to October the earth goes halfway around the Sun. So midnight in April and midnight in October are exactly opposite directions.

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3 years ago

When the sound from two sound waves goes up and down (loud, soft, loud, soft) it makes a distinctive sound pattern called beats.

djverab [1.8K]

The beats are actually two new sounds.

Their frequencies are (the sum of the original two frequencies) and (the difference of the original two frequencies).

The existence of the beats is the result of the difference in the frequencies of the original two sounds. <em> (b)</em>

8 0

3 years ago

Read 2 more answers

Can someone please solve this

Zina [86]

Answer:

The gravity is pulling the diver downwards but the rotation of the body means gravity cant pull him down as quickly

Explanation:

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3 years ago

How are the mass and weight of an object related? Include a description with words and an equation.

nikdorinn [45]

The weight is the force experienced, whereas the mass represents the actual quantity of matter inside a body..
weigh on the surface of the earth is equal to mg
mass is m
and at the centre weight is 0 due to 0 acceleration that's 0 g
but mass is always constant and remains m, no matter where you are

6 0

2 years ago

A child has an ear canal that is 1.3 cm long. Assume the speed of sound is v = 344 m/s.

kap26 [50]

Answer:

The frequencies are $(f, f_1) = (6615.4 \ Hz , 19846.2\ Hz)$

Explanation:

From the question we are told that

The length of the ear canal is $l = 1.3 \ cm =\frac{1.3}{100} = 0.013 \ m$

The speed of sound is assumed to be $v_s = 344 \ m/s$

Now taking look at a typical ear canal we see that we assume it is a closed pipe

Now the fundamental harmonics for the pipe(ear canal) is mathematically represented as

$f = \frac{v_s}{4 * l }$

substituting values

$f = \frac{344}{4 * 0.013 }$

$f = 6615.4 \ Hz$

Also the the second harmonic for the pipe (ear canal) is mathematically represented as

$f_1 = \frac{3v_s}{4 * l}$

substituting values

$f_1 = \frac{3 * 344}{4 * 0.013}$

$f_1 = 19846.2 \ Hz$

Given that sound would be loudest in the pipe at the frequency, it implies that the child will have an increased audible sensitivity at this frequencies

6 0

3 years ago