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xxTIMURxx [149]
3 years ago
13

The tower crane is used to hoist a 2.0mg- load upward at constant velocity. The 1.7Mg- jib BD and 0.6-Mg jib BC have centers of

mass at G1 and G2, respectively.
Determine the required mass of the counterweight C so that the resultant moment produced by the load and the weight of the tower crane jibs about point A is zero.
The center of mass for the counterweight is located at G3.

Physics
1 answer:
Ksivusya [100]3 years ago
3 0
This is a classic problem in statics. The counterweight is placed so that the tower crane would be stable, or the total moment is zero. There are four sources of torques: the load, the jib BD, the jib BC, and the counter weight. Staring with the total moment equals zero, and taking clockwise moments as positive. The units of moment here is Mg * m.

M = 0
(2.0)(12.5) + (1.7)(9.5) - (0.6)(4) - (C)(7.5) = 0
7.5C = 38.75
C = 5.17 Mg

Therefore, the counterweight must be 5.17 Mg.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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4 years ago
A system that can be affected by the outside environment, by an exchange of matter or energy is ______.
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A system that can be affected by the outside environment, by an exchange of matter or energy is an open physical system .

4 0
2 years ago
Two spectators at a soccer game in Montjuic Stadium see, and a moment later hear, the ball being kicked on the playing field. Th
Akimi4 [234]

Answer:

a) The distance of spectator A to the player is 79.2 m

b) The distance of spectator B to the player is 43.9 m

c) The distance between the two spectators is 90.6 m

Explanation:

a) Knowing the time it takes the sound to reach both spectators, we can calculate their position relative to the player, using this equation:

x = v * t

where:

x = position of the spectators

v = speed of sound

t = time

Then, the position for spectator A relative to the player is:

x = 343 m/s * 0.231 s = 79.2 m

b)For spectator B:

x = 343 m/s * 0.128 s

x = 43.9 m

The distance of spectator A and B to the player is 79.2 m and 43.9 m respectively.

c) To calculate the distance between the spectators, please see the attached figure. Notice that the distance between the spectators is the hypotenuse of the triangle formed by the sightline of both. We already know the longitude of the two sides. Then, using Pythagoras theorem:

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(Distance AB)² = (79.2 m)² + (43.9 m)²

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6 0
3 years ago
An ocean wave traveling in one direction has a wavelength of 1.0 m and a frequency of 1.25 Hz. Take the direction of wave propag
aliina [53]

Answer:

a) v=1*1.25=1.25\: m/s

b) y(x,t)=2sin(2\pi( x-1.25 t)  

c) y(3,10)=1.73 m    

Explanation:

a) The speed of a wave is given by the following equation:

v=\lambda f

Where:

λ is the wavelength

f is the frequency

v=1*1.25=1.25\: m/s

b) The harmonic wave has the following equation:

y=Asin(kx-\omega t)

A is the amplitude (2 m)

k is the wavenumber (2π/λ)  

ω is the angular frequency (2πf)

y(x,t)=2sin(2\pi x-2\pi*1.25 t)  

y(x,t)=2sin(2\pi( x-1.25 t)  

c) Here we need to find the heigth at x=3 m and t =10 s, so we need to find y(3,10).

y(3,10)=2sin(2\pi(3-1.25*10)

y(3,10)=2sin(2\pi(3-1.25*10)              

y(3,10)=1.73 m              

I hope it helps you!

 

6 0
3 years ago
A water tank is filled with water. What will be the pressure of the water when the level of the water is 6m?
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Answer:

pressure = density x g x height

= 1000 x 10 x 6 Pascal

=60000 Pascal

OR 60 kP

3 0
3 years ago
Read 2 more answers
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