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xxTIMURxx [149]
3 years ago
13

The tower crane is used to hoist a 2.0mg- load upward at constant velocity. The 1.7Mg- jib BD and 0.6-Mg jib BC have centers of

mass at G1 and G2, respectively.
Determine the required mass of the counterweight C so that the resultant moment produced by the load and the weight of the tower crane jibs about point A is zero.
The center of mass for the counterweight is located at G3.

Physics
1 answer:
Ksivusya [100]3 years ago
3 0
This is a classic problem in statics. The counterweight is placed so that the tower crane would be stable, or the total moment is zero. There are four sources of torques: the load, the jib BD, the jib BC, and the counter weight. Staring with the total moment equals zero, and taking clockwise moments as positive. The units of moment here is Mg * m.

M = 0
(2.0)(12.5) + (1.7)(9.5) - (0.6)(4) - (C)(7.5) = 0
7.5C = 38.75
C = 5.17 Mg

Therefore, the counterweight must be 5.17 Mg.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Answer:

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Explanation:

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A car speeds past a stationary police officer while traveling 135 km/h. the officer immediately begins pursuit at a constant acc
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(a) The time it takes for the police officer to catch up to the speeding car is determined as 0.31 s.

(b) The speed of the police officer  at the time he catches up to the driver is 136.8 km/h.

<h3>Time of motion of the police</h3>

The time taken for the police to catch up with the driver is calculated as follows;

v = at

where;

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t = 11.4 seconds

(v1 - v2)t = ¹/₂at² --- (1)

(v1 - v2)t = v1²/2a --- (2)

From (1):

(v1 - 37.5)t = ¹/₂(3.278)t²

(v1 - 37.5)t = 1.639t²

v1 - 37.5 = 1.639t

v1 = 1.639t + 37.5  -----(3)

From (2):

(v1 - 37.5)t = v1²/(2 x 3.278)

(v1 - 37.5)t = 0.153 ----- (4)

solve 3 and 4;

(1.639t + 37.5 - 37.5)t = 0.153

1.639t² = 0.153

t² = 0.0933

t = 0.31 s

<h3>Speed of the police officer</h3>

v1 = 1.639(0.31) + 37.5 = 38 m/s = 136.8 km/h

Learn more about velocity here: brainly.com/question/4931057

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