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Mazyrski [523]
3 years ago
5

you push a box across the floor with a force of 30n you it 15 meters in 8 seconds. how much work did you do how much power did y

ou see
Physics
2 answers:
Naddika [18.5K]3 years ago
7 0
20m/s newtons per second 


Vadim26 [7]3 years ago
3 0

Answer : W = 450 J and P =  56.25 Watts

Explanation :

It is given that,

Force, F = 30 N

Distance, d = 15 m

Time, t = 8 sec

The work done is given as :

W = F.d

W=30\ N\times 15\ m

W = 450\ J

So, the work done to push a box across the floor is 450 N.

Mechanical power is defined as,

P=\dfrac{Work}{time}

P=\dfrac{450\ J}{8\ s}

P = 56.25 Watt

The power is 56.25 Watts.

Hence, this is the required solution.

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look at the attachment above ☝️

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A liquid has a volume of 100 cm and a mass of 85g.
djyliett [7]

Answer:

B. Its density is lower than that of water

Explanation:

density = mass / volume

density of the liquid = 85 / 100 = 0.85 g/cm^3

now,

density of water is 1 g/cm^3 which is greater than the density of the given liquid ( 0.85 g/cm^3 )

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Consider the hydrogen atom as described by the Bohr model. The nucleus of the hydrogen atom is a single proton. The electron rot
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To solve this problem we will apply the concept of centripetal acceleration. This type of acceleration is described as the product between the square of the angular velocity and the turning radius. Mathematically the expression can be expressed as

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r = Radius

Our values are given as,

\omega = 4.12*10^{16}rad/s

r = 5.29*10^{-11}

Replacing,

a_c = (4.12*10^{16})^2( 5.29*10^{-11})

a_c = 8.979*10^{22}m/s^2

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7 0
3 years ago
All the different habitats in our world make up
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All the different habitats in our world make up biodiversity

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4 0
2 years ago
Read 2 more answers
A motorboat is moving at 4.0 m/s when it begins to accelerate at 1.0 m/s2. To the nearest tenth of a second, how long does it ta
vaieri [72.5K]

Answer:

13 sec

Explanation:

Hello

by definition the acceleration is a vector derived magnitude that indicates the speed variation per unit of time

a=\frac{V_{f}-V_{i}}{t_{f}-t_{i}}\\a(t_{f}-t_{i})={V_{f}-V_{i}  }}\\t_{f}-t_{i}=\frac{V_{f}-V_{i}}{a} \\\\t_{f}=\frac{V_{f}-V_{i}}{a}+t_{i} \\\\

Let

Vi=4.0 m/s

a=1.0 m/s2

Vf=17.0 m/s

ti= (0)sec

t2= unknown

t_{f}=\frac{V_{f}-V_{i} }{a}+t_{i}\\t_{f}=\frac{17-4 }{1}+0\\t_{f}=\ 13\ sec\\

Answer: 13 sec

I hope it helps

8 0
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