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Mazyrski [523]
3 years ago
5

you push a box across the floor with a force of 30n you it 15 meters in 8 seconds. how much work did you do how much power did y

ou see
Physics
2 answers:
Naddika [18.5K]3 years ago
7 0
20m/s newtons per second 


Vadim26 [7]3 years ago
3 0

Answer : W = 450 J and P =  56.25 Watts

Explanation :

It is given that,

Force, F = 30 N

Distance, d = 15 m

Time, t = 8 sec

The work done is given as :

W = F.d

W=30\ N\times 15\ m

W = 450\ J

So, the work done to push a box across the floor is 450 N.

Mechanical power is defined as,

P=\dfrac{Work}{time}

P=\dfrac{450\ J}{8\ s}

P = 56.25 Watt

The power is 56.25 Watts.

Hence, this is the required solution.

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Suppose a plot of 1/λ vs f has a slope of 0.728, what is the wave velocity? Give only the numerical answer with 4 decimal place
Charra [1.4K]

Answer:

The wave velocity is 1.3736

Explanation:

A plot of inverse of wavelength (λ) versus frequency (f), can be analyzed as follows;

The vertical axis will be 1/λ and the horizontal axis will be f

slope = (Δ1/λ)/(Δf)

        = 1/(fλ)

∴ 1/(fλ) = 0.728

From wave equation, V = fλ

where;

V is the wave velocity

f is the frequency of the wave

λ is the wavelength

1/(fλ) = 0.728

1/(V) = 0.728

V = (0.728)⁻¹

V = 1.3736

Therefore, the wave velocity is 1.3736

3 0
3 years ago
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zhuklara [117]

Answer:

Respect the client’s decision

Explanation:

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2 years ago
A mass spectrometer is being used to separate common oxygen-16 from the much rarer oxygen-18, taken from a sample of old glacial
Nataly_w [17]

Answer:

0.092 m

Explanation:

A charged moving particle immersed in a region with magnetic field follows a circular trajectory at constant speed (uniform circular motion), since the magnetic forces acts perpendicular to the direction of motion of the particle.

Since the magnetic force acts as centripetal force, we can write:

qvB=m\frac{v^2}{r}

where

q is the charge of the particle

v is its velocity

B is the strength of the magnetic field

m is the mass of the particle

r is the radius of the orbit

Solving the equation for r,

r=\frac{mv}{qB}

For the ion of oxygen-16, we have:

m_A=2.66\cdot 10^{-26}kg

q_A = 1.6\cdot 10^{-19}C (it is singly charged)

v_A=2.90\cdot 10^6 m/s

B_A=1.30 T

So the radius of its orbit is

r_A=\frac{m_A v_A}{q_A B_A}=\frac{(2.66\cdot 10^{-26})(2.90\cdot 10^6)}{(1.6\cdot 10^{-19})(1.30)}=0.371 m

For the ion of oxygen-18, we have:

m_B = \frac{18}{16}m_A = 2.99\cdot 10^{-26}kg

q_B = 1.6\cdot 10^{-19}C (it is singly charged)

v_B=2.90\cdot 10^6 m/s

B_B=1.30 T

So the radius of its orbit is

r_B=\frac{m_B v_B}{q_B B_B}=\frac{(2.99\cdot 10^{-26})(2.90\cdot 10^6)}{(1.6\cdot 10^{-19})(1.30)}=0.417 m

After each ion has travelled a semicircle, the separation between the two ions will be twice the difference in their radius, so:

d=2(r_B-r_A)=2(0.417-0.371)=0.092 m

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3 years ago
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Akimi4 [234]
D.) White Dwarf

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Here, M = mass of the Sun.

Hope this helps!
3 0
3 years ago
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