5 ml=5 cm³ , density=mass/volume=45/5= 9 g/cm³ therefore answer B
Answer:
The standard enthalpy of formation of ethanoic acid is -484 kJ/mol.
Explanation:
...[1]
..[2]
..[3]
The standard enthalpy of formation of ethanoic acid :
..[4]
Using Hess's law to calculate :
2 × [1] + 2 × [2] - [3] = [4]


The standard enthalpy of formation of ethanoic acid is -484 kJ/mol.
I'd say b, but i'm not 100 percent sure.<span />
Answer:The answer is 3...I think
Explanation:
143
Sig Figs
3
Decimals
0
Scientific Notation
1.43 × 102