Question

A 36.2 g object has a heat capacity of 12.5 J/ oC. How much energy (in J) is required to raise the temperature by 5.73 oC?

Answer 1

Answer:

$\Delta H=2592.825\ J$

Explanation:

The expression for the calculation of the enthalpy change of a process is shown below as:-

$\Delta H=m\times C\times \Delta T$

Where,  

$\Delta H$  is the enthalpy change

m is the mass

C is the specific heat capacity

$\Delta T$  is the temperature change

Thus, given that:-

Mass of object = 36.2 g

Specific heat = 12.5 J/g°C

$\Delta T=5.73\ ^0C$

So,  

$\Delta H=36.2\times 12.5\times 5.73\ J=2592.825\ J$

$\Delta H=2592.825\ J$

Answer 2

Answer:71.625J

Explanation:Energy(Q)=mCpT

But recall that they said heat capacity (C), not specific heat capacity(cp)....Heat capacity=Mass *cp,but the heat capacity was clearly given so the mass is irrelevant in this case.

Energy (Q)=Heat capacity*Temperature change

Energy=12.5*5.73=71.625J