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Serggg [28]
3 years ago
13

When an excited electron in an atom moves to the ground state, the electron

Chemistry
2 answers:
kodGreya [7K]3 years ago
7 0

Answer is: (4) emits energy as it moves to a lower energy state.

Atom emits a characteristic set of discrete wavelengths, according to its electronic energy levels.

Emission spectrum of a chemical element is the spectrum of frequencies emitted due to an atom making a transition from a high energy state to a lower energy state.  

Each transition has a specific energy difference.  

Each element's emission spectrum is unique.


likoan [24]3 years ago
3 0

When an excited electron in an atom moves to the ground state, the electron  \boxed{\left( {\text{4}} \right){\text{ emits energy as it moves to a lower energy state}}}.

Further Explanation:

Electronic transition:

It is a process that occurs when an electron undergoes emission or absorption from one energy level to another energy level.

When an electron undergoes a transition from a lower energy level to a higher energy level then it requires energy to complete the process. This transition is an absorption process.

When an electron undergoes a transition from higher energy level to lower energy level then it emits energy to complete the process. This transition is an emission process.

An excited electron has higher energy than that present in the ground state of the atom. Energy is to be released when an excited electron returns to its ground state. Therefore the excited electron emits energy when it jumps from an excited state (higher energy state) to the ground state (lower energy state). Hence option (4) is the correct answer.

Learn more:

1. Which transition is associated with the greatest energy change? brainly.com/question/1594022

2. Describe the spectrum of elemental hydrogen gas: brainly.com/question/6255073

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Atomic structure

Keywords: electronic transition, absorption, emission, lower, higher, energy level, excited state, ground state, emit, lower energy state.

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Answer:

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General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
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Explanation:

<u>Step 1: Define</u>

83.1 g CaBr₂

<u>Step 2: Identify Conversions</u>

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Molar Mass of CaBr₂ - 40.08 + 2(79.90) = 199.88 g/mol

<u>Step 3: Convert</u>

<u />83.1 \ g \ CaBr_2(\frac{1 \ mol \ CaBr_2}{199.88 \ g \ CaBr_2} ) = 0.415749 mol CaBr₂

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.415749 mol CaBr₂ ≈ 0.416 mol CaBr₂

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