Question

A 40.0-L sample of fluorine is heated from 90.0°C to 186.0°C. What volume will the sample occupy at the higher temperature?

Answer 1

Answer:

The volume will be 82.67 L

Explanation:

Charles's Law is the relationship between the volume and temperature of a certain amount of ideal gas. In this way, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

$\frac{V}{T} = k$

Having a certain volume of gas V1 that is at a temperature T1 at the beginning of the experiment, by varying the volume of gas to a new value V2, then the temperature will change to T2, and it will be true:

$\frac{V1}{T1} =\frac{V2}{T2}$

In this case, you know:

• V1= 40 L
• T1= 90 °C
• V2= ?
• T2= 186 °C

Replacing:

$\frac{40L}{90C} =\frac{V2}{186 C}$

Solving:

$V2=\frac{40L}{90C} *186 C$

V2= 82.67 L

The volume will be 82.67 L