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Karo-lina-s [1.5K]
4 years ago
8

A sound can be ________ or _________.

Physics
1 answer:
s2008m [1.1K]4 years ago
7 0
A.
Sorry if it’s wrong
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force of 200n nice

Explanation:

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If you run North for 5 meters and then East for 15 meters and then
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1m/s

Explanation:

D = 22m

T = 22s

S = 22÷22

= 1 m/s

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A is the correct answer: 100 degrees C is the boiling point of water, just subtract 82 from 100.
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A rocket is fired at a speed of 75.0 m/s from ground level, at an angle of 60.0° above the horizontal. The rocket is fired towar
Leni [432]

Answer:

ΔH = 33.17m

Explanation:

By knowing the amount of time it takes the rocket to travel the horizontal 27m, we will be able to calculate the height when x=27m. So:

X = V_{o}*cos(60)*t   where X=27m; V_{o}=75m/s

Solving for t:

t=0.72s

Now we calculate the height of the rocket:

Y_{f}=V_{o}*sin(60)*t-\frac{g*t^{2}}{2} = 44.17m

If the wall was 11m-high, the difference is:

ΔH = 33.17m

6 0
4 years ago
B. a student attaches a nozzle with an exit radius that is n times smaller than the faucet radius. 2b) let n = 3 i. how will thi
JulijaS [17]

Part a)

Flow rate is defined as rate of volume flow

it is determined by

Q = \frac{dV}{dt}

now if the radius of pipe is reduced then we assume here that liquid flow is ideal flow here and there is no change in the density of liquid.

So here we know that since mass is always conserved

so

\frac{dm}{dt}_{in} = \frac{dm}{dt}_{out}

so we have

\rho\frac{dV}{dt}_{in} = \rho\frac{dV}{dt}_{out}

\frac{dV}{dt}_{in} = \frac{dV}{dt}_{out}

now we can say from above equation that there is no effect on the flow rate is we change the radius of pipe

Part b)

now in order to find the speed of flow'

\frac{dV}{dt}_{in} = \frac{dV}{dt}_{out}

A_{in}v_{in} = A_{out}v_{out}

\pi r^2 v_{in} = \pi (\frac{r}{n})^2 v_{out}

v_{in} = \frac{v_{out}}{n^2}

so final speed will be

v_{out} = n^2 v_{in}

here we have n = 3

v_{out} = 9* v_{in}

so flow speed will be 9 times more than initial speed

6 0
3 years ago
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