Answer:
the distance from the location of the center of gravity to the location of the center o mass for this system is 1.13m
Explanation:
Given that
m₁=4.4kg
x₁=+1.1m
m₂=3.7kg
x₂=+0.80m
m₃=2.9kg
x₃=+1.6m
The position of the center of mass is
Xcm = [m₁x₁ +m₂x₂ +m₃x₃]/(m₁+m₂+m₃)
= [(4.40kg)(1.1 m)+(3.70 kg)(0.80 m)+(2.90 kg)(1.60 m)]/(4.4 kg + 3.70 kg+2.90 kg)
= 1.13 m
The position of the center of gravity is 1.13m
Therefore, the distance from the location of the center of gravity to the location of the center o mass for this system is 1.13m
Answer:
The correct answers are It is the resistance of an object to changes in its motion, and It is a force
Given:
ρ = 13.6 x 10³ kg/m³, density of mercury
W = 6.0 N, weight of the mercury sample
g = 9.81 m/s², acceleration due to gravity.
Let V = the volume of the sample.
Then
W = ρVg
or
V = W/(ρg)
= (6.0 N)/[(13.6 x 10³ kg/m³)*(9.81 m/s²)]
= 4.4972 x 10⁻⁵ m³
Answer: The volume is 44.972 x 10⁻⁶ m³
