<span>assuming the pitch is 100yards long, the player runs 100yards to the other goal then a further 50 yards back to the 50-yard line. So he/she runs 150yards in 18s
150/18 = 8.33yards per second average speed.
Initial velocity = 0, average velocity =8.33
Vav = (Vinitial+Vfinal)/2
Vav = 4.16m/s</span>
- Mass of the elevator (m) = 570 Kg
- Acceleration = 1.5 m/s^2
- Distance (s) = 13 m
- Let the force be F.
- We know, F = ma,
- Therefore, F = (570 × 1.5) N = 855 N
- Angle between distance and force (θ) = 0°
- We know, work done = F s Cos θ
- Therefore, work done by the cable during this part
- = (855 × 13 × Cos 0°) J
- = (855 × 13 × 1) J
- = 11115 J
<u>Answer</u><u>:</u>
<u>1</u><u>1</u><u>1</u><u>1</u><u>5</u><u> </u><u>J</u>
Hope you could get an idea from here.
Doubt clarification - use comment section.
Answer:
i3 =11.014A
i5 = 3.15A
Explanation:
Here according to k'chofs first law
i1 =i2 + i3
i3 = i4 + i5
For determine the i1 you have to consider the resultant resistor of the system
4 , 1 and 3 resistors are in pararel
Then, Resultant is
1/4 + 1/1 + 1/3 = 1/ R
R = 12/19
For get total we have to add another remaining 3 resistor because of serious
Then Resultant is = 12/19 + 3
= 69/19
Then using V = IR
40 =i3* 69/19
i3 = 11.014 A
Other 3 resistors are parrarel because of this voltage of those resistors are same.
Then i inversely propotional to its resistor
Then ,
i5 * 2 = (i3-i5)*4/5
i 5 = 3.15 A
consider the velocity towards the pitcher as positive
m = mass of the baseball = 0.145 kg
v₀ = initial velocity of the baseball = - 39 m/s
v = final velocity of the baseball = 52 m/s
t = time of contact = 3 x 10⁻³ sec
F = average force between bat and ball
Using impulse-change in momentum equation
F t = m (v - v₀ )
F (3 x 10⁻³) = (0.145) (52 - (- 39))
F = 4398.33 N