Answer:
Explanation:
Given
Required
Solve
Apply law of indices
Evaluate 10^5
Hence:
What is the reducing agent in the reaction below?
2 answers:
Option (a) is correct.
A reducing agent is the one which loses electrons to other substance and an oxidizing agent is one which accepts electrons.
Here, In
, Cr has oxidation number 6+ in the L.H.S of the equation, but on R.H.S its oxidation number is 0 i.e. it Cr has gained electrons such that total charge is 0.
And the oxidation state of Al in the left-hand side of equation is 0 and in right-hand side, it is +6.i.e. it has donated its electrons to Cr.
Hence, Cr is the oxidizing agent and Al is the reducing agent.
A reducing agent is the one which loses electrons to other substance and an oxidizing agent is one which accepts electrons.
Here, In
And the oxidation state of Al in the left-hand side of equation is 0 and in right-hand side, it is +6.i.e. it has donated its electrons to Cr.
Hence, Cr is the oxidizing agent and Al is the reducing agent.
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The highlighted atoms have sp2 - sp3 hybridization. The highlighted atoms are carbon and nitrogen as shown.
The structure of Xanthine is shown in the image attached to this answer. The indicated atoms are Carbon and nitrogen as shown. Let us remember that hybridization has to do with the mixing of atomic orbitals to form appropriate hybrid orbitals that are suitable for overlap with orbitals of other atoms.
The highlighted carbon atom is sp2 hybridized because it has a carbon nitrogen double bond while the highlighted nitrogen atom is sp3 hybridized. Therefore, the highlighted atoms have sp2 - sp3 hybridization.
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