Answer: 18g
Explanation:
1 mle of glucose combusts to give 6moles of CO2 and 6moles of H2O
C6H12O6 + 6O2-------- 6CO2 + 6H2O at STP.
Multiplying 6 by 3 moles we have 18 g of CO2
Answer:
Silver and copper
Explanation:
Siliver
Electrical conductivity=62000000(s/m)
Boiling point=2162
Melting point=961.78
Phase=solid
Copper
Electrical conductivity=59000000(s/m)
Boiling point =2927
Melting point=1084.62
Phase=soild
Metals like gold, silver and copper are drawn into thin wire and are used in an electric circuit because of their high electrical conductivity
Mostly Siliver and copper are used since using gold is much expensive.
The reaction between NaOH and HCl is as follows
NaOH + HCl ---> NaCl + H₂O
for neutralisation, H⁺ ions react with an equivalent amount of OH⁻ ions.
Number of NaOH moles reacted = 0.270 M/1000 mL/L x 37 mL = 0.00999 mol
number of HCl moles reacted = 0.270 M/1000 mL x 27 mL = 0.00729 mol
HCl reacts with NaOH in 1:1 molar ratio
Number of excess NaOH moles remaining - 0.00999 - 0.00729 = 0.0027 mol
total volume of solution = 37 mL + 27 mL = 64 mL = 0.064 L
Since there's excess OH⁻ ions, we can calculate pOH value first
pOH = - log [OH⁻]
[OH⁻] = 0.0027 mol / 0.064 L = 0.042 mol/L
pOH = -log(0.042 M)
pOH = 1.37
by knowing pOH we can calculate pH using the following equation;
pH + pOH = 14
pH = 14 - 1.37
pH = 12.63
Answer:
C.
Explanation:
Section 1 and section 4 are balanced.
