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Olegator [25]
3 years ago
8

Please help

Chemistry
1 answer:
Kay [80]3 years ago
5 0

Answer:

Can you post the pic to it so I can give you more info?

Explanation:

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A 42.0g sample of compound containing only C and H was analyzed. The results showed that the sample contained 36.0g of C and 6.0
user100 [1]

Answer:

What is the empirical formula of the compound?

Explanation:

When the relative masses of elements in a hydrocarbon are given, it is possible to use this information to obtain the empirical formula by dividing the given masses of each element by the relative atomic masses of the element. The lowest ratio is now used to divide through to obtain the empirical formula of the compound.

The empirical formula only shows that ratio of atoms of each element present in the compound. From the information provided, the empirical formula of the compound is CH2. Hence the answer.

5 0
3 years ago
How many protons and electrons are contained in an<br> atom of element 44?
vitfil [10]

Answer:

44

Explanation:

protons and electrons have the same number:)

5 0
3 years ago
Read 2 more answers
What is the energy change associated with 1.5 mole of D being formed? 
AleksandrR [38]

Answer:

–36 KJ.

Explanation:

The equation for the reaction is given below:

2B + C —› D + E. ΔH = – 24 KJ

From the equation above,

1 mole of D required – 24 KJ of energy.

Now, we shall determine the energy change associated with 1.5 moles of D.

This can be obtained as illustrated below:

From the equation above,

1 mole of D required – 24 KJ of energy

Therefore,

1.5 moles of D will require = 1.5 × – 24 = –36 KJ.

Therefore, –36 KJ of energy is associated with 1.5 moles of D.

3 0
2 years ago
If a quadrilateral has three angels measuring 60, 45 and 100 find the measure of the fourth angel
Nina [5.8K]
The sum of angels of a quadrilateral is equal to 360°.

∠A = 360 - (60 + 45 + 100) = 155
7 0
3 years ago
a gas is contained in a thick walled balloon. when the pressure changes from 417 mm hg to 576 mm hg, the volume changes from l t
melomori [17]
We can use the combined gas law equation to solve for the initial volume
\frac{P1V1}{T1} =  \frac{P2V2}{T2}
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
substituting the values in the equation 
\frac{417 mmHg*V}{497 K} =  \frac{576mmHg*4.78L}{386K}
V = 8.50 L
the initial volume is 8.50 L
7 0
2 years ago
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