Describe the changes in the field of view and the amount of available light when going from low to high power using the compound
1 answer:
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Answer:
Explanation:
Let the thickness of the film is t and the refractive index of the material of film is n.
When light travels through a sheet of thickness t, the optical path traveled is nt.
When the path of one of slit is covered by a sheet of thickness t, the optical path becomes
x = ( n - 1) t
As the one fringe is shift, so the optical path changed by one wavelength.
i.e., x = λ
So, λ = ( n - 1) t
Answer:
Assuming that both mass here move horizontally on a frictionless surface, and that this spring follows Hooke's Law, then the mass of would be four times that of
.
Explanation:
In general, if the mass in a spring-mass system moves horizontally on a frictionless surface, and that the spring follows Hooke's Law, then
.
Here's how this statement can be concluded from the equations for a simple harmonic motion (SHM.)
In an SHM, if the period is , then the angular velocity of the SHM would be
.
Assume that the mass starts with a zero displacement and a positive velocity. If represent the amplitude of the SHM, then the displacement of the mass at time
would be:
.
The velocity of the mass at time would be:
.
The acceleration of the mass at time would be:
.
Let represent the size of the mass attached to the spring. By Newton's Second Law, the net force on the mass at time
would be:
,
Since it is assumed that the mass here moves on a horizontal frictionless surface, only the spring could supply the net force on the mass. Therefore, the force that the spring exerts on the mass will be equal to the net force on the mass. If the spring satisfies Hooke's Law, then the spring constant will be equal to:
.
Since , it can be concluded that:
.
For the first mass , if the time period is
, then the spring constant would be:
.
Similarly, for the second mass , if the time period is
, then the spring constant would be:
.
Since the two springs are the same, the two spring constants should be equal to each other. That is:
.
Simplify to obtain:
.
Answer:
The change in potential energy is
Explanation:
From the question we are told that
The magnitude of the uniform electric field is
The distance traveled by the electron is
Generally the force on this electron is mathematically represented as
Where F is the force and q is the charge on the electron which is a constant value of
Thus
Generally the work energy theorem can be mathematically represented as
Where W is the workdone on the electron by the Electric field and is the change in kinetic energy
Also workdone on the electron can also be represented as
Where considering that the movement of the electron is along the x-axis
So
substituting values
Now From the law of energy conservation
Where is the change in potential energy
Thus