Answer:
μk = 0.26885
Explanation:
Conceptual analysis
We apply Newton's second law:
∑Fx = m*a (Formula 1)
∑F : algebraic sum of the forces in Newton (N)
m : mass in kilograms (kg)
a : acceleration in meters over second square (m/s²)
Data:
a= -0.9 m/s²,
g = 9.81 m/s² : acceleration due to gravity
W= 75 N : Block weight
W= m*g
m = W/g = 75/9.8= 7.65 kg : Block mass
Friction force : Ff
Ff= μk*N
μk: coefficient of kinetic friction
N : Normal force (N)
Problem development
We apply the formula (1)
∑Fy = m*ay , ay=0
N-W-25 = 0
N = 75
+25
N= 100N
∑Fx = m*ax
20-Ff= m*ax
20-μk*100
= 7.65*(-0.90 )
20+7.65*(0.90) = μk*100
μk = ( 20+7.65*(0.90)) / (100)
μk = 0.26885
Answer:
K = 1.29eV
Explanation:
In order to calculate the kinetic energy of the proton you first take into account the uncertainty principle, which is given by:
(1)
Δx : uncertainty of position = 2.0pm = 2.0*10^-12m
Δp: uncertainty of momentum = ?
h: Planck's constant = 6.626*10^-34 J.s
You calculate the minimum possible value of Δp from the equation (1):

The minimum kinetic energy is calculated by using the following formula:
(2)
m: mass of the proton = 1.67*10^{-27}kg

in eV you have:

The kinetic energy of the proton is 1.29eV
48 inches go restaurant vector is 14 inches Long and right angle
First, let us calculate for the volume of the block of
lead using the formula:
V = l * w * h
But we have to convert all units in terms of cm:
l = 2.0 dm = 20 cm
w = 8 cm
h = 3.5 cm
Therefore the volume is:
V = (20 cm) * (8 cm) * (3.5 cm)
V = 560 cm^3
Next we convert the mass in terms of g:
m = 6.356 kg = 6356 g
Density is mass over volume, so:
density = 6356 g / 560 cm^3
density = 11.35 g / cm^3 (ANSWER)