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kkurt [141]
3 years ago
6

An object is moving in the absence of a net force. Which of the following best describes the object's motion? -please help?

Physics
2 answers:
Gelneren [198K]3 years ago
7 0
You can solve this by using Newton's First Law or Newton's Second Law.

1) Newton's First Law or Inertia Law states that in the abscense of a net force acting over an object, this will not chage its state of movement, i.e it will  remain at rest (if it is no moving) or with uniform movement (if the object is moving).

2) Newton's Second Law: Net force = mass * acceleration => acceleration = net force / mass = 0 / mass = 0.

Zero accelerations means rest or uniform movement.

First Law is implicit in Second Law.
anzhelika [568]3 years ago
7 0
There are two cases in which no net force is being applied on an object:
1) The object is stationary
2) The object is not accelerating; that is, the magnitude or direction of its velocity is not changing.
Because this question requires the object to be in motion, the velocity of this object must be constant but non-zero.
Therefore, the correct option would be the one where the velocity is constant and in a straight line. (circular motion means the velocity's direction is constantly changing, thus the velocity is not constant)
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A 75 N box of oranges is being pushed across a horizontal floor. As it moves, it is slowing at a constant rate of 0.90 m/s each
shusha [124]

Answer:

μk = 0.26885

Explanation:

Conceptual analysis

We apply Newton's second law:

∑Fx = m*a (Formula 1)

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

Data:

a= -0.9  m/s²,  

g = 9.81 m/s² : acceleration due to gravity

W= 75 N :  Block weight

W= m*g  

m =  W/g = 75/9.8= 7.65 kg :  Block mass

Friction force : Ff

Ff= μk*N

μk: coefficient of kinetic friction

N : Normal force (N)  

Problem development

We apply the formula (1)

∑Fy = m*ay    , ay=0

N-W-25 = 0

N = 75 +25

N= 100N

∑Fx = m*ax    

20-Ff= m*ax    

20-μk*100 = 7.65*(-0.90 )

20+7.65*(0.90) = μk*100

μk = ( 20+7.65*(0.90)) / (100)

μk = 0.26885

4 0
3 years ago
a nonrelativistic proton is confined to a length of 2.0 pm on the x-axis. what is the kinetic energy of the proton if its speed
Elina [12.6K]

Answer:

K = 1.29eV

Explanation:

In order to calculate the kinetic energy of the proton you first take into account the uncertainty principle, which is given by:

\Delta x \Delta p\geq \frac{h}{4\pi}      (1)

Δx : uncertainty of position = 2.0pm = 2.0*10^-12m

Δp: uncertainty of momentum = ?

h: Planck's constant = 6.626*10^-34 J.s

You calculate the minimum possible value of Δp from the equation (1):

\Delta p=\frac{h}{4\pi \Delta x}=\frac{6.626*10^{-34}J.s}{4\pi(2.0*10^{-12}m)}\\\\\Delta p=2.63*10^{-23}kg.\frac{m}{s}

The minimum kinetic energy is calculated by using the following formula:

k=\frac{(\Delta p)^2}{2m}       (2)

m: mass of the proton = 1.67*10^{-27}kg

k=\frac{(2.63*10^{-23}kgm/s)^2}{2(1.67*10^{-27}kg)}=2.08*10^{-19}J

in eV you have:

2.08*10^{-19}J*\frac{6.242*10^{18}eV}{1J}=1.29eV

The kinetic energy of the proton is 1.29eV

7 0
3 years ago
Two vectors, X and Y, form a right angle. Vector X is 48 inches long and vector Yis 14 inches long. The length of
Troyanec [42]
48 inches go restaurant vector is 14 inches Long and right angle
6 0
3 years ago
Help! Don’t understand any of this!!
Kryger [21]
Yea me either. Good look
5 0
3 years ago
A block of lead with dimensions 2.0 dm x 8.0 cm x 35 mm, has a mass of 6.356 kg. calculate the density of lead in g/cm
insens350 [35]

First, let us calculate for the volume of the block of lead using the formula:

V = l * w * h

But we have to convert all units in terms of cm:

l = 2.0 dm = 20 cm

w = 8 cm

h = 3.5 cm

 

Therefore the volume is:

V = (20 cm) * (8 cm) * (3.5 cm)
V = 560 cm^3

 

Next we convert the mass in terms of g:

m = 6.356 kg = 6356 g

 

Density is mass over volume, so:

density = 6356 g / 560 cm^3

density = 11.35 g / cm^3     (ANSWER)

8 0
3 years ago
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