Answer:
= (πD
)/R
Explanation:
If we define the magnitude of the field as B, then we have:
Total magnitude of the field = magnitude of the field B_loop + magnitude of the field B_wire. The total magnitude is equivalent to zero. Therefore, the field B_loop has an inward direction while the field B_wire has an outward direction.
B_loop = (μ0)*()/2*R
B_wire = (μ0)*()/2*π*D
Thus:
B_loop = B_wire at the center of the loop.
(μ0)*()/2*R = (μ0)*(
)/2*π*D
= (πD
)/R
MAGNITUDE AND DIRECTION OF A VECTOR
Given a position vector →v=⟨a,b⟩,the magnitude is located by |v|=√a2+b2. The direction is equal to the angle formed with the x-axis, or with the y-axis, depending on the application. For a position vector, the direction is found by tanθ=(ba)⇒θ=tan−1(ba)
<h3>What is the formula of magnitude?</h3>
The formula to determine the extent of a vector (in two dimensional space) v = (x, y) is: |v| =√(x2 + y2). This formula is derived from the Pythagorean theorem. the procedure to determine the magnitude of a vector (in three dimensional space) V = (x, y, z) is: |V| = √(x2 + y2 + z2)
To learn more about magnitude and direction, refer
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main answer is given below,
