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2 years ago

Poop ppppppppppppppppppppppppppppppp

Physics

2 answers:

pantera1 [17]2 years ago

8 0

Answer:

thanks for the points man

arlik [135]2 years ago

3 0

Answer:

pop pop pop pop

Explanation:

brainliest?

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If the weight of a submerged object is equal to the buoyant force, what net force acts upon the object?

Y_Kistochka [10]

Answer:

Explanation:

The weight is acting downwards where as the buoyant force acting upwards (opposite) direction with equal amount of force. so the opposite forces cancel out each other (because of the force amount being equal) and no net force is acting on the object.

Hope i have helped you

Thanks.

7 0

3 years ago

A person holding a lunch bag is moving upward in a hot air balloon at a constant speed of 7.3 m/s . When the balloon is 24 m abo

Kitty [74]

Explanation:

Given that,

Initial speed of the bag, u = 7.3 m/s

Height above ground, s = 24 m

We need to find the speed of the bag just before it reaches the ground. It can be calculated using third equation of motion as :

$v^2=u^2+2as$

$v^2=(7.3)^2+2\times 9.8\times 24$

$v=\sqrt{523.69}$

v = 22.88 m/s

So, the speed of the bag just before it reaches the ground is 22.38 m/s. Hence, this is the required solution.

8 0

2 years ago

What is the mass of a baseball thrown at 25 m/s resulting in a momentum of 10 kg·m/s?

Tresset [83]

Answer: m = 0.4 kg

Explanation: Momentum is the product of mass and velocity also expressed in this equation:

p = m x v

Derive to find m

m = p / v

= 10 kg•m/s / 25 m/s

= 0.4 kg

8 0

3 years ago

Are Constellations based on the magnitude of stars.

Nikolay [14]

Constellations are based off of many Greek and Roman fables. Many of their gods and beliefs are pictured in the stars, which is where we get most of our constellations. Hope this helps!

4 0

3 years ago

Read 2 more answers

Four traveling waves are described by the following equations, where all quantities are measured in SI units and y represents th

agasfer [191]

Answer:

$T_1=T_3=\dfrac{2\pi}{21}$

$T_2=T_4=\dfrac{2\pi}{42}$

Explanation:

Wave 1, $y_1=0.12\ cos(3x-21t)$

Wave 2, $y_2=0.15\ sin(6x+42t)$

Wave 3, $y_3=0.13\ cos(6x+21t)$

Wave 4, $y_4=-0.27\ sin(3x-42t)$

The general equation of travelling wave is given by :

$y=A\ cos(kx\pm \omega t)$

The value of $\omega$ will remain the same if we take phase difference into account.

For first wave,

$\omega_1=21$

$\dfrac{2\pi }{T_1}=21$

$T_1=\dfrac{2\pi}{21}$

For second wave,

$\omega_2=42$

$\dfrac{2\pi }{T_2}=42$

$T_2=\dfrac{2\pi}{42}$

For the third wave,

$\omega_3=21$

$\dfrac{2\pi }{T_3}=21$

$T_3=\dfrac{2\pi}{21}$

For the fourth wave,

$\omega_4=42$

$\dfrac{2\pi }{T_4}=42$

$T_4=\dfrac{2\pi}{42}$

It is clear from above calculations that waves 1 and 3 have same time period. Also, wave 2 and 4 have same time period. Hence, this is the required solution.

3 0

3 years ago